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Fantom [35]
1 year ago
14

When ethanol (C2H6O(aq)) is consumed, it reacts with oxygen gas (O2) in the body to produce gaseous carbon dioxide and liquid wa

ter. Enter the balanced chemical equation for the reaction
Chemistry
2 answers:
ankoles [38]1 year ago
6 0

Answer:

C2H6O(aq) + 3O2(g) → 2CO2(g) + 3H2O(l)

Explanation:

Step 1: data given

The reactants are:

ethanol = C2H6O(aq)

oxygen gas = O2(g)

The products are:

gaseous carbon dioxide = CO2(g)

liquid water = H2O(l)

Step 2: The unbalanced equation

C2H6O(aq) + O2(g) → CO2(g) + H2O(l)

Step 3: Balancing the equation

C2H6O(aq) + O2(g) → CO2(g) + H2O(l)

On the left side we have 2 time C (in C2H6O), on the right side we have 1x C (in CO2). To balance the amount of C on both sides, we have to multiply CO2 on the right side by 2.

C2H6O(aq) + O2(g) → 2CO2(g) + H2O(l)

On the left side we have 6x H (in C2H6O), on the right side we have 2x H(in H2O). To balance the amount of H on both sides, we have to multiply H2O on the right side by 3.

C2H6O(aq) + O2(g) → 2CO2(g) + 3H2O(l)

On the right side we have 7x O (4x O in 2CO2 and 3x O in 3H2O), on the left side we have 3x O (1x in C2H6O and 2x in O2). To balance the amount of O on both sides, we have to multiply O2 on the left side by 3. Now the equation is balanced.

C2H6O(aq) + 3O2(g) → 2CO2(g) + 3H2O(l)

jonny [76]1 year ago
5 0

Answer:

C₂H₆O + 3 O₂ → 2 CO₂ + 3 H₂O

Explanation:

Ethanol (C₂H₆O) is processed by the body when reacts with oxygen (O₂) producing carbon dioxide (CO₂) and water (H₂O). The unbalanced reaction is:

C₂H₆O + O₂ → CO₂ + H₂O

As you can see, ethanol contains 2 atoms of carbon, that means must be produced 2 CO₂:

C₂H₆O + O₂ → <em>2</em> CO₂ + H₂O

Also, ethanol contains 6 atoms of hydrogen that produced 3 molecules of water:

C₂H₆O + O₂ → <em>2</em> CO₂ + <em>3</em> H₂O

Now, with carbon and hydrogen balanced, there are produced 7 atoms of oxygen. As ethanol contains 1 atom of oxygen. 3 moles of O₂ must react in the beginning. Thus, balanced reaction is:

C₂H₆O + <em>3</em> O₂ → <em>2</em> CO₂ + <em>3</em> H₂O

You might be interested in
A solution of sodium acetate (ch3coona) in water is weakly basic. <br> a. True <br> b. False
guajiro [1.7K]
Hello!

The statement that a solution of sodium acetate (CH₃COONa) is weakly basic is true:

Sodium acetate is the conjugate base of Acetic Acid. When sodium acetate is dissolved in water, it follows the equation that is shown below:

CH₃COONa(s) → CH₃COO⁻(aq) + Na⁺(aq)

Now the Acetate (CH₃COO⁻) ion, has an equilibrium in water to produce hydroxyl (OH⁻) ions and (Acetic Acid CH₃COOH)

CH₃COO⁻ + H₂O ⇄ CH₃COOH + OH⁻

This is a weak equilibrium, and the hydroxyl ions cause the solution to be weakly basic.

Have a nice day!
7 0
2 years ago
Calculate the specific heat capacity for a 22.7-g sample of lead that absorbs 237 J when its temperature increases from 29.8 °C
soldier1979 [14.2K]

Answer:

\boxed {\boxed {\sf c\approx 0.159 \ J/ g \textdegree C}}

Explanation:

We are asked to find the specific heat capacity of a sample of lead. The formula for calculating the specific heat capacity is:

c= \frac{Q}{m \times \Delta T}

The heat absorbed (Q) is 237 Joules. The mass of the lead sample (m) is 22.7 grams. The change in temperature (ΔT) is the difference between the final temperature and the initial temperature. The temperature increases <em>from</em> 29.8 °C <em>to </em>95.6 °C.

  • ΔT = final temperature -inital temperature
  • ΔT= 95.6 °C - 29.8 °C = 65.8 °C

Now we know all three variables and can substitute them into the formula.

  • Q= 237 J
  • m= 22.7 g
  • ΔT = 65.8 °C

c= \frac {237 \ J}{22.7 \ g  \ \times  \ 65.8 \textdegree C}

Solve the denominator.

  • 22.7 g * 65.8 °C = 1493.66 g °C

c= \frac {237 \  J}{1493.66 \ g \textdegree C}

Divide.

c= 0.1586706479 J /g \textdegree C

The original values of heat, temperature, and mass all have 3 significant figures, so our answer must have the same. For the number we found that is the thousandth place. The 6 in the ten-thousandth place tells us to round the 8 up to a 9.

c \approx 0.159 \ J/g \textdegree C

The specific heat capacity of lead is approximately <u>0.159 Joules per gram degree Celsius.</u>

3 0
1 year ago
50cm3 of sodium hydroxide solution was titrated against a solution of sulfuric acid. The concentration of the sodium hydroxide s
miskamm [114]

Answer:

49 g/L is the concentration of the acid

Explanation:

Firstly, we proceed to write the equation of reaction.

2NaOH + H2SO4 ——-> Na2SO4 + 2H2O

We can see that 1 mole of the base reacted with two moles of the acid.

kindly note that dm^3 is same as liter

Firstly, we need to get the concentration of the reacted sulphuric acid in g/L

we use the simple titration equation below;

CaVa/CbVb = Na/Nb

From the question;

Ca = ?

Va = 25 cm^3

Cb = 20 g/L

we convert this to concentration in mol/L

Mathematically, that is concentration in g/L divided by molar mass in g/mole

molar mass of NaOH = 40 g/mol

so we have; 20g/L / 40 = 0.5 mol/L

Vb = 50 cm^3

Na = 1

Nb = 2

Where C represents concentrations, V volumes and N , number of moles

Now, substitute the values;

Ca * 25/0.5 * 50 = 1/2

25Ca/25 = 0.5

So Ca = 0.5 mol/L

Now to get the concentration of H2SO4 in g/L

What we do is to multiply the concentration in mol/L by molar mass in g/mol

That would be 0.5 * 98 = 49 g/L

4 0
2 years ago
Beer brewing begins with steeping grains in hot water, releasing the sugars inside. The sugar water is then heated to a boil and
user100 [1]

Answer:

The answers to the question are

a. 166.64 ° F

b. 217990.08 J/hour or 60.55 J/s = 60.55 watts

c. 13.C

Explanation:

a. To solve the question we list out the given variables thus

mass of grain = 16.5 lbs

Temperature of grain = 67 °F

Volume of hot water = 5 gals = ‪0.02273‬ m³

Equilibrium temperature of the mixture = 154 °F

Specific heat capacity of the grain = 0.44 times specific heat capacity  of water

Therefore we have

Heat supplied by hot water = heat gained by mixture

Density of the water = 997 kg/m³ which gives

Therefore the mass of the water = (Density of the water) × (Volume of the water) = (997 kg/m³) × ‪(0.02273‬ m³) = 22.66181 kg

Therefore the heat supplied by the water =22.66 kg×1000 g/kg ×4.2 J/g°C×(Tₓ -‪67.78 °C) = ‪7.48 kg×1000 g/kg×0.44×4.2 J/g°C×(67.78 -‪19.44)

= 95172 × (Tₓ -‪67.78 °C) =668205.7536 J

(Tₓ -‪67.78 °C) = 7.02 from where Tₓ = 74.80 °C = ‪166.64 ° F

The initial temperature (strike temperature) of the hot water = 74.80 °C = 166.64 ° F

b. Where the mixture lost two degrees we have

22.66 kg×1000 g/kg ×4.2 J/g°C×2 °C + ‪7.48 kg×1000 g/kg×0.44×4.2 J/g°C×2  °C = 217990.08 J therefore the average energy lost per unit time = 217990.08 J/hour or 60.55 J/s

c. To find out how much it cost we have

Heat energy required to raise 5 gallons of water from 110 °F to 166.64 °F we have

22.66 kg×1000 g/kg ×4.2 J/g°C×(74.8 °C-‪43.33 °C) = 2994745.92 J

Energy lost during the heating = 10% = 299474.59 J

Total energy supplied 2994745.92 J + 299474.59 J  = 3294220.5 J

Time for heating = 47 minutes, therefore rate of energy consumption = (3294220.5 J)/ (47×60) = 1168.163 Watt 1.168 kW

Cost of energy = 15.C per kilowatt-hour therefore 1.168 kW for 47 minutes will cost

1.168 kW ×47/60×15 = 13.C

therefore it cost 13.C to heat the 5 gallons of tap water initially at 110 ° F to the strike temperature 166.64 °F

6 0
1 year ago
An aluminum ion has a charge of +3, and an oxide has a charge of -2. What would be the product of a reaction between these two e
kozerog [31]

The product of a reaction between these two elements is Al_{2} O_{3}.

Explanation:

The oxidation state of an ion in a compound is equal to its charge.

The aluminum having a charge of +3 because oxidation state is +3

The oxide is having charge of -2

The product of these reactants will produce a chemical compound.

The compound formed is Al_{2} O_{3}  i.e Aluminium oxide. The compound while getting formed will share the charge and cation A+ will have the charge of anion and anion will have the charge of cation. This will result in a compound as there should be a neutral charge on the compound formed.

The <em>+</em><em>3 charge of the cation Al+ will go to anion oxide O2- and the charge of anion -2 will go with cation Al+. </em>

<em />

8 0
2 years ago
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