Answer: The concentration of excess ![[OH^-]](https://tex.z-dn.net/?f=%5BOH%5E-%5D)
in solution is 0.017 M.
Explanation:
1. 
moles of 
1 mole of 
give = 1 mole of 
Thus 0.019 moles of give = 0.019 mole of
2. moles of 
According to stoichiometry:
1 mole of 
gives = 2 moles of 
Thus 0.012 moles of give = 
moles of
As 1 mole of neutralize 1 mole of
0.019 mole of will neutralize 0.019 mole of
Thus (0.024-0.019)= 0.005 moles of will be left.
![[OH^-]=\frac{\text {moles left}}{\text {Total volume in L}}=\frac{0.005}{0.3L}=0.017M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D%5Cfrac%7B%5Ctext%20%7Bmoles%20left%7D%7D%7B%5Ctext%20%7BTotal%20volume%20in%20L%7D%7D%3D%5Cfrac%7B0.005%7D%7B0.3L%7D%3D0.017M)
Thus molarity of in solution is 0.017 M.
None of the above.
1 mole filled with gas at STP occupies
=22.4 L
∴ 3mole of kr gas at STP occupies
= 3 × 22.4
= 67.2 L
Answer:
CuSO4 + Fe -> FeSO4 + Cu
Explanation:
This reaction is a classic example of a redox reaction. I won't go in too deep, but the basic thing is that electrons from the Fe atom go to the Cu2+ ion. Therefore, Fe becomes an ion, and Cu - an electroneutral atom:
Fe + Cu2+ -> Fe2+ + Cu.
Silver is not a very reactive metal and it does not give up its electrons to Cu.
Answer:
The concentration after 20 mins is 0.832 M
Explanation:
Zero order rate law is given by;
R = K [A₀]⁰
A zero order reaction, rate is independent of the initial concentration
R = K
Where;
R is the rate of reaction
K is the rate constant = 0.0416 M/min
Since R = K,
Then, R = 0.0416 M/min
After 20 min, the concentration will be;
A = Rt
A = (0.0416 M/min)(20 min)
A = 0.832 M
Therefore, the concentration after 20 mins is 0.832 M
