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Greeley [361]
2 years ago
7

You probably already know the names of some molecules. Identify which compound (water, salt, carbon dioxide, or methane) corresp

onds to each of the following chemical formulas. H2O is . CO2 is . NaCl is . CH4 is .
Chemistry
2 answers:
vladimir1956 [14]2 years ago
7 0

CO2 is carbon

H2O is water

CH4 is methane

NaCI is salt

Natali5045456 [20]2 years ago
6 0

Explanation:

Water has a formula which represents two hydrogen atoms are attached to one oxygen atom. Therefore, the formula of water is H_{2}O.

Salt is also known as sodium chloride. Its formula represents that one sodium atom is attached to one chlorine atom, therefore, its formula is NaCl.

Carbon dioxide has a formula which represents one carbon atom is attached to two oxygen atoms. Therefore, its formula is CO_{2}.

Methane has a formula which represents one carbon atom is attached to four hydrogen atoms. Therefore, its formula is CH_{4}.

Thus, we can conclude that H_{2}O is water, CO_{2} is carbon dioxide, NaCl is salt, and CH_{4} is methane.


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Calculate the hydroxide ion concentration [oh-] for human urine (ph = 6.2). notice this is about hydroxide.
igomit [66]

[OH⁻] = 1.6 × 10⁻⁸ mol / dm³

<h3>Explanation</h3>

By definition, [\text{H}^{+}] = 10^{-\text{pH}}, where [\text{H}^{+}] is the concentration of proton in the solution.

pH = 6.2 for this solution. As a result, [\text{H}^{+} = 10^{-6.2} = 6.31 \times 10^{-7} \; \text{mol} \cdot \text{dm}^{-3}.

[\text{H}^{+}] \cdot [\text{OH}^{-}] = \text{K}_w, where [\text{OH}^{-}] the concentration of hydroxide ions and \text{K}_w is the dissociation constant of water.

\text{K}_w = 10^{-14} \; \text{mol}\cdot \text{dm}^{-3} at 0.10 MPa and 25 °C. As a result, [\text{OH}^{-}] = \text{K}_w / [\text{H}^{+}] = 10^{14} / (6.31 \times 10^{-7}) = 1.6 \times 10^{-8} \; \text{mol}\cdot \text{dm}^{-3}.

5 0
2 years ago
The highest energy occupied molecular orbital in the b−b bond of the b2 molecule is _____
statuscvo [17]
According to molecular orbital theory, atomic orbitals combine to form molecular orbital. Number of molecular orbitals are equal to number of atomic orbitals. Further, of the total number of molecular orbitals, half are called as bonding molecular orbital while remaining are anti-bonding molecular orbital. In case, if system contains lone pair of electrons, they occupy non-bonding molecular orbital. Highest occupied molecular energy levels are referred as HOMO, while lowest unoccupied molecular energy levels are referred as LUMO.

In case of B2 molecule, two B atoms combines to generate molecular orbitals. Attached is  the MOT diagram of B2 molecule

From the attached figure, it is clearly evitable that high occupied energy level in B2 is π. Also, it must be noted both <span>pi molecular orbitals i.e. Pi 2Px and Pi 2Py at highest energy level (occupied).</span>

6 0
2 years ago
Read 2 more answers
Given the following reactions Fe2O3 (s) + 3CO (s) → 2Fe (s) + 3CO2 (g) ΔH = -28.0 kJ 3Fe (s) + 4CO2(s) → 4CO (g) + Fe3O4(s) ΔH =
Taya2010 [7]

Answer: The enthalpy of the reaction is -109 kJ

Explanation:

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

Fe_2O_3(s)+3CO(s)\rightarrow 2Fe(s)+3CO_2(g)   \Delta H=-28.0kJ  \times 3    

3Fe_2O_3(s)+9CO(s)\rightarrow 6Fe(s)+9CO_2(g)   \Delta H=-84.0kJ     (1)

3Fe(s)+4CO_2(s)\rightarrow 4CO(g)+Fe_3O_4(s) \Delta H=+12.5kJ  \times 2  

6Fe(s)+8CO_2(s)\rightarrow 8CO(g)+2Fe_3O_4(s) \Delta H=+25.0kJ     (2)

The final reaction is:

Subtracting (2) from (1):

3Fe_2O_3(s)+CO(g)\rightarrow CO_2(g)+2Fe_3O_4(s) \Delta H=-84.0-(+25.0)=-109kJ

Thus the enthalpy of the reaction is -109 kJ

7 0
2 years ago
5. A Dumas bulb is filled with chlorine gas at the ambient pressure and is found to contain 7.1 g of chlorine when the temperatu
kati45 [8]

Answer:

a. The original temperature of the gas is 2743K.

b. 20atm.

Explanation:

a. As a result of the gas laws, you can know that the temperature is inversely proportional to moles of a gas when pressure and volume remains constant. The equation could be:

T₁n₁ = T₂n₂

<em>Where T is absolute temperature and n amount of gas at 1, initial state and 2, final states.</em>

<em />

<em>Replacing with values of the problem:</em>

T₁n₁ = T₂n₂

X*7.1g = (X+300)*6.4g

7.1X = 6.4X + 1920

0.7X = 1920

X = 2743K

<h3>The original temperature of the gas is 2743K</h3><h3 />

b. Using general gas law:

PV = nRT

<em>Where P is pressure (Our unknown)</em>

<em>V is volume = 2.24L</em>

<em>n are moles of gas (7.1g / 35.45g/mol = 0.20 moles)</em>

R is gas constant = 0.082atmL/molK

And T is absolute temperature (2743K)

P*2.24L = 0.20mol*0.082atmL/molK*2743K

<h3>P = 20atm</h3>

<em />

7 0
2 years ago
Students working in lab accidentally spilled 17 l of 3.0 m h2so4 solution. they find a large container of acid neutralizer that
bogdanovich [222]

Answer is: 8568.71 of baking soda.

Balanced chemical reaction: H₂SO₄ + 2NaHCO₃ → Na₂SO₄ + 2CO₂ + 2H₂O.

V(H₂SO₄) = 17 L; volume of the sulfuric acid.

c(H₂SO₄) = 3.0 M, molarity of sulfuric acid.

n(H₂SO₄) = V(H₂SO₄) · c(H₂SO₄).

n(H₂SO₄) = 17 L · 3 mol/L.

n(H₂SO₄) = 51 mol; amount of sulfuric acid.

From balanced chemical reaction: n(H₂SO₄) : n(NaHCO₃) = 1 :2.

n(NaHCO₃) = 2 · 51 mol.

n(NaHCO₃) = 102 mol, amount of baking soda.

m(NaHCO₃) = n(NaHCO₃) · M(NaHCO₃).

m(NaHCO₃) = 102 mol · 84.007 g/mol.

m(NaHCO₃) = 8568.714 g; mass of baking soda.

4 0
2 years ago
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