How much heat is released during the formation of 3.18 mol HCl(g) in this reaction: H2(g)+Cl2(g) → 2HCl(g) with a H of -184.6 kJ
2 answers:
Answer: 293.5kJ
Explanation: As can be seen from the given reaction:
As of the reaction is negative, it means the heat is released and the reaction is exothermic.
When 2 moles of HCl are produced, energy released is 184.6kJ
When 3.18 moles of HCl are produced, energy released will be
The given thermochemical reaction is between hydrogen gas and chlorine gas to form hydrogen chloride.
This can be represented as:
Δ
=-184.6 kJ/mol
So when two moles of HCl is formed, 184.6 kJ of energy is released.
Calculating the heat released when 3.18 mol HCl (g) is formed in the reaction:
Therefore, 293.5 kJ of heat is released when 3.18 mol HCl is formed in the reaction between hydrogen and chlorine.
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Answer:
a. 123.9°C
b.
c.
Explanation:
Hello, I'm attaching a picture with the numerical development of this exercise.
a. Since the steam is overheated vapour, the specific volume is gotten from the corresponding table. Then, as it became a saturated vapour, we look for the interval in which the same volume of state 1 is, then we interpolate and get the temperature.
b. Now, at 80°C, since it is about a rigid tank (constant volume for every thermodynamic process), the specific volume of the mixture is 0.79645 m^3/kg as well, so the specific volume for the liquid and the vapour are taken into account to get the quality of 0.234.
c. Now,since this is an isocoric process, the heat transfer per kg of steam is computed as the difference in the internal energy, considering the initial condition (showed in a. part) and the final one computed here.
** The thermodynamic data were obtained from Cengel's thermodynamics book 7th edition.
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