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2 years ago

How many moles of Helium gas are in a balloon with a volume of 6.452 L at 99.7 kPa

Chemistry

1 answer:

Taya2010 [7]2 years ago

8 0

Answer:

n = 0.26 mol.

Explanation:

Given,

Pressure, P = 99.7 kPa = 1 atm

where 101.325 kPa = 1 atm

P = 0.984 atm

Temperature, T = 297 K

Volume = 6.452 L

Now, using ideal gas equation

PV = n RT

0.984 x 6.452 = n x 0.08206 x 297

n = 0.26 mol.

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Which solution contains the largest number of moles of chloride ions?

elixir [45]

Molarity = number of moles of solute/liters of solution
number of moles of solute = molarity x liters of solution

Part (a): 30.00 ml of 0.100m Cacl2
number of moles of CaCl2 = 0.1 x 0.03 = 3x10^-3 moles
1 mole of CaCl2 contains 2 moles of chlorine, therefore 3x10^-3 moles of CaCl2 contains 6x10^-3 moles of chlorine

Part (b): 10.0 ml of 0.500m bacl2
number of moles of BaCl2 = 0.5 x 0.01 = 5x10^-3 moles
1 mole of BaCl2 contains 2 moles of chlorine, therefore 5x10^-3 moles of BaCl2 contains 10x10^-3 moles of chlorine

Part (c): 4.00 ml of 1.000m nacl
number of moles of NaCl = 1 x 0.004 = 0.004 moles
1 mole of NaCl contains 1 mole of chlorine, therefore 4x10^-3 moles of NaCl contains 4x10^-3 moles of chlorine

Part (d): 7.50 ml of 0.500m fecl3
number of moles of FeCl3 = 0.5 x 0.0075 = 3.75x10^-3 moles
1 mole of FeCl3 contains 3 moles of chlorine, therefore 3.75x10^-3 moles of FeCl3 contains 0.01125 moles of chlorine

Based on the above calculations, the correct answer is (d)

5 0

2 years ago

Read 2 more answers

a gas that exerts a pressure of 215 torr in a container with a volume of 51.0 mL will exert a pressure of ? torr when transferre

zhannawk [14.2K]

To calculate the new pressure, we can use Boyle’s law to relate these two scenarios (Boyle’s law is used because the temperature is assumed to remain constant). Boyle’s law is:

P1V1 = P2V2,

Where “P” is pressure and “V” is volume. The pressure and volume of the first scenario is 215 torr and 51 mL, respectively, and the second scenario has a volume of 18.5 L (18,500 mL) and the unknown pressure - let’s call that “x”. Plugging these into the equation:

(215 torr)(51 mL) =(“x” torr)(18,500 mL)
x = 0.593 torr

The final pressure exerted by the gas would be 0.593 torr.

Hope this helps!

3 0

2 years ago

What is the mass, in g, of 0.500 mol of 1,2-dibromoethane, CH2BrCH2Br?

inna [77]

Molar mass CH2BrCH2Br = 188.0 g/mol

1 mole ---------- 188.0 g
0.500 moles ----- ?

mass = 0.500 * 188.0 / 1

= 94.0 g

Answer C

hope this helps!

4 0

2 years ago

A chunk of dry ice, solid CO2, "disappears" after sitting at room temperature for a while. There is no puddle of liquid. What ha

Vika [28.1K]

I believe the answer is A.

8 0

2 years ago

Be sure to answer all parts. Draw the structure of a compound of molecular formula C4H8O that has a signal in its 13C NMR spectr

GenaCL600 [577]

Answer:

The possible structures are ketone and aldehyde.

Explanation:

Number of double bonds of the given compound is calculated using the below formula.

$N_{db}=N_{c}+1-\frac{N_{H}+N_{Br}-N_{N}}{2}$

$N_{db}$ =Number of double bonds

$N_{c}$ = Number of carbon atoms

$N_{H}$ = Number of hydrogen atoms

$N_{N}$ = Number of nitrogen atoms

The number of double bonds in the given formula - $C_{4}H_{8}O$

$N_{db}= 4+1-\frac{8+0-0}{2}=1$

The number of double bonds in the compound is one.

Therefore, probable structures is as follows.

(In attachment)

The structures I and III are ruled out from the probable structures because the signal in 13C-NMR appears at greater than 160 ppm.

alkene compounds I and II shows signal less than 140 ppm.

Hence, the probable structures III and IV are given as follows.

The carbonyl of structure I appear at 202 and ketone group of IV appears at 208 in 13C, which are greater than 160.

Hence, the molecular formula of the compound $C_{4}H_{8}O$ having possible structure in which the signal appears at greater than 160 ppm are shown aw follows.

8 0

2 years ago