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Nikitich [7]
1 year ago
13

Which element can form a chloride with a general formula of MCl2 or MCl3

Chemistry
1 answer:
zhannawk [14.2K]1 year ago
5 0
Oxidation state number can be used to determine the unknown element in these two compounds. They are used to determine how many electrons are given, taken or shared to form compounds.

Recall the elementary rules of oxidation numbers.

1. The sum of all oxidation numbers in a neutral compound is zero.
2. Chlorine, bromine, iodine have oxidation number of -1 ( except compounds with fluorine and oxygen)

Let oxidation number of element M be x.
Check rule 2. Chlorine has -1 oxidation number.

Now we write an equation of MCl₂ (neutral compound)
x + (2 * -1)= 0 ⇒ x₁= +2

For MCl₃
x + (3 * -1)=  0 ⇒ x₂= +3

So element has 2 different oxidation number in compounds, +2 and +3.

The element is iron (Fe) since it has +2 and +3  oxidation numbers in the compounds.

You need to learn it by hard. Unfortunately there is not an easier way to work out with these oxidation numbers.

The answer is iron (Fe).

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x = 63

z = 117

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Explanation:

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5 0
2 years ago
What is the molarity of a solution that contains 2.35 g of nh3 in 0.0500 l of solution?
tankabanditka [31]
The molarity is the number of moles in 1 L of the solution. 
The mass of NH₃ given - 2.35 g
Molar mass of NH₃ - 17 g/mol
The number of NH₃ moles in 2.35 g - 2.35 g / 17 g/mol = 0.138 mol
The number of moles in 0.05 L solution - 0.138 mol 
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Therefore molarity of NH₃ - 2.76 M
3 0
1 year ago
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150.0 grams of AsF3 were reacted with 180.0 g of CCl4 to produce AsCl3 and CCl2F2. The theoretical yield of CCl2F2 produced, in
Kamila [148]
The chemical reaction would be written as 

2 AsF3<span> + 3 CCl4 = 2 AsCl3 + 3 CCl2F2
</span>
We use the given amounts of the reactants to first find the limiting reactant. Then use the amount of the limiting reactant to proceed to further calculations.

150 g AsF3 ( 1 mol / 131.92 g) = 1.14 mol AsF3
180 g CCl4 (1 mol / 153.82 g) = 1.17 mol CCl4

 Therefore, the limiting reactant would be CCl4 since it would be consumed completely. The theoretical yield would be:

1.17 mol CCl4 ( 3 mol CCl2F2 / 3 mol CCl4 ) = 1.17 mol CCl2F2

7 0
1 year ago
A 8.5-liter sample of a gas at 2.0 atm and 300.0 K has 1.2 moles of the gas. If 0.65 mole of the gas is added to the sample at t
hodyreva [135]

Did you take the test? what was the answer Im stuck on this one too

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Anarel [89]

Answer:

Chemicals A and B form an endothermic reaction, and chemicals C and D form an exothermic reaction.

Explanation:

The reaction that produced chemical C is an endothermic reaction whereas, the reaction between C and D is an exothermic one.

An exothermic change is one in which heat is liberated to the surroundings. So the surrounding becomes hotter at the end of the reaction.

An endothermic reaction is a change in which heat is absorbed from the surrounding and hence the surrounding colder at the end of the change.

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