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sladkih [1.3K]
2 years ago
15

How many moles are contained in 325 gram sample of ammonium dichromate (NH4)2Cr2O7

Chemistry
1 answer:
svetlana [45]2 years ago
3 0

Answer:

Hyba odpowiedzi c. Hyba

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if the charcoal from an ancient fire contains 1/512 amount of carbon-14 as a living tree, how long ago did the fire occur? the h
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11.19 half lives

Explanation:

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Give a possible explanation for the relative amounts of the isometric methyl nitrobenzoates formed in the nitration reaction. Co
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Answer:

The electrophilic aromatic substitution reaction nitration is used to nitrate methyl benzoate and acetanilide with a nitronium ion. Crystallization was used to purify the product. The melting point was used to determine its purity and the regiochemistry of the products.

Explanation:

Methyl m-Nitrobenzoate is formed in this

reaction rather that ortho/para isomers

because of the ester group of your starting

product of methylbenzoate. The functional

group of ester is a electron withdrawing group

causing nitrobenzene (N02) to become in the

meta position. Thus N02 is a deactivating

group causing itself to be a meta director.

Basically you must look at the substituents

that are attached to your starting benzene ring

in order to figure out whether your reaction

with be ortho/para directors or meta

directors. If the substituents are electron

withdrawing groups then you will be left with

meta as your product but if your substituents

are electron donating groups then your

product will be ortho/para.

4 0
2 years ago
a gas sample is heated from -20.0 C to 57.0 C and the volume is increased from 2.00L to 4.50L. If the initial pressure is 0.109a
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2 years ago
The graph shows the amount of a gaseous product formed over time during two trials of a reaction. A different concentration of a
ss7ja [257]

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Trial 2, because the amount of product formed per unit time is higher.

Explanation:

Message me for extra help.

8 0
2 years ago
Read 2 more answers
In a group assignment, students are required to fill 10 beakers with 0.720 M CaCl2. If the molar mass of CaCl2 is 110.98 g/mol a
8_murik_8 [283]
The answer is 200 g.

If the molar mass of CaCl2 is 110.98 g/mol, this means there are 110.98 g in 1 L of 1 M solution.
Let's find how many g of CaCl2 are present in 0.720 M.
110.98 g : 1 M = x : 0.720 M
x = 110.98 g * 0.720 M : 1 M 
x = 79.90 g

So there are 79.90 g in 0.720 M. In other words, in 1 L of 0.720 M solution there will be  79.90 g.

Now, we need to prepare ten beakers with 250 mL of solutions:
10 * 250 mL = 2500 mL = 2.5 L

79.90 g : 1 L = x : 2.5 L
x = 79.90 g * 2.5 L : 1 L
x = 199.75 g ≈ 200 g
8 0
2 years ago
Read 2 more answers
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