Question

A small hole in the wing of a space shuttle requires a 20.7-cm2 patch, (a) What is the patch's area in square kilometers (km2)? (b) If the patching material costs NASA $3.25/in2. What is the cost of the patch?

Answer 1

Answer:

(a) The area of space shuttle is $2.07\times 10^{-9} km^2$.

(b) $10.427 is the cost of the patch.

Explanation:

Area of the patch of the space shuttle = $20.7 cm^2$

a) 1 cm = 0.00001 km

$1 cm^2= (0.00001 km)^2=10^{-10}km^2$

$20.7 cm^2=20.7\times 10^{-10}km^2=2.07\times 10^{-9} km^2$

b) 1 cm = 0.393701 inch

$1 cm ^2=0.1550 inch^2$

$20.7 cm^2=20.7\times 0.1550 inch^2=3.2085 inch^2$

Cost of patching area = $\ 3.25/inch^2$

Cost of patching $3.2085 inch^2$ are:

$\ 3.25/inch^2\times 3.2085 inch^2=\ 10.427$