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Valentin [98]
2 years ago
11

In the reaction CuO(s) + CO2(g) → CuCO3(s), a. CO2 is the Lewis acid and CuCO3 is its conjugate base. b. O2– acts as a Lewis bas

e and Cu2+ acts as a Lewis acid. c. CuO is the Lewis acid and CuCO3 is its conjugate base. d. O2– acts as a Lewis base and CO2 acts as a Lewis acid. e. Cu2+ acts as a Lewis acid and CO32– acts as a Lewis base.
Chemistry
1 answer:
adoni [48]2 years ago
4 0

<u>Answer:</u> The correct answer is Option d.

<u>Explanation:</u>

According to Lewis acid-base concept:

The substance which is donating electron pair is considered as Lewis base and the substance which is accepting electron pair is considered as Lewis acid.

For the given chemical reaction:

CuO(s)+CO_2(g)\rightarrow CuCO_3(s)

CO_2 is accepting electron pair and is getting converted to CO_3^{2-}. Thus, it is considered as Lewis acid.

O^{2-} present in CuO is a Lewis base because it is donating electron pair.

Thus, the correct answer is Option d.

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Answer: The stick model method

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2 years ago
How many miles of Fe2+ ions and MnO4- ions were titrated in each part 1 trial
Fudgin [204]

Answer:

In 1000 ml there is 0.10 moles of Fe 2+

Therefore, in 10 ml there is (0.1/1000)*10= 0.001 mol of Fe2+

mole ratio for rxn Fe2+ : MnO4- is

1 : 2

therefore if 0.001 moles of Fe2+ react then 0.001*2 =0.002 moles of MnO4- react with Fe2+

hence, molarity of MnO4- = (mol*vol)/1000

= 0.002*10.75/1000= 2.15*10-5M

Explanation:

Hope this helps

5 0
2 years ago
Which statement is correct? Salts are formed by the reaction of bases with water. Most salts are ionic and are soluble in water.
Studentka2010 [4]
<span>Salts are formed by the reaction of bases with water. -  FALSE
</span><span>Most salts are ionic and are soluble in water. -  TRUE
</span><span>Most salts are insoluble in water and lack electrical charges. - FALSE
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3 0
2 years ago
Read 2 more answers
HA and HB are two strong monobasic acids. 25.0cm3 of 6.0mol/dm3 HA is mixed with 45.0cm3 of 3.0mol/dm3 HB.
Lostsunrise [7]

Answer:

The H+ (aq) concentration of the resulting solution is 4.1 mol/dm³

(Option C)

Explanation:

Given;

concentration of HA, C_A = 6.0mol/dm³

volume of HA, V_A  = 25.0cm³, = 0.025dm³

Concentration of HB, C_B = 3.0mol/dm³

volume of HB, V_B = 45.0cm³ = 0.045dm³

To determine the H+ (aq) concentration in mol/dm³ in the resulting solution, we apply concentration formula;

C_iVi = C_fV_f

where;

C_i is initial concentration

V_i is initial volume

C_f is final concentration of the solution

V_f is final volume of the solution

C_iV_i = C_fV_f\\\\Based \ on \ this\ question, we \ can \ apply\ the \ formula\ as;\\\\C_A_iV_A_i + C_B_iV_B_i = C_fV_f\\\\C_A_iV_A_i + C_B_iV_B_i = C_f(V_A_i\ +V_B_i)\\\\6*0.025 \ + 3*0.045 = C_f(0.025 + 0.045)\\\\0.285 = C_f(0.07)\\\\C_f = \frac{0.285}{0.07} = 4.07 = 4.1 \ mol/dm^3

Therefore, the H+ (aq) concentration of the resulting solution is 4.1 mol/dm³

7 0
2 years ago
Gaseous cyclobutene undergoes a first-order reaction to form gaseous butadiene. At a particular temperature, the partial pressur
Gnoma [55]

Answer:

41.3 minutes

Explanation:

Since the reaction is a first order reaction, therefore, half life is independent of the initial concentration, or in this case, pressure.

t_{1/2}= \frac{0.693}{K}

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n here is number of half life

therefore, \frac{1}{8}= \frac{1}{2}^3

⇒ n= 3

it took 124 minutes to drop pressure to 1/8 of original value, half life = 124/3= 41.3 minutes.

8 0
2 years ago
Read 2 more answers
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