Answer:
Number of moles nitric acid in the cylinder is 400.539g/mol.
Explanation:
From the given,
Weight of empty gas cylinder ![W_{1}= 90.0 lb= 40823.3 gramsWeight of full cylinder[tex]W_{2} = 116.5 lb= 52843.511 gramsThe critical temperature = 287 KThe critical pressure 54.3 LMolar mass of nitric acid = [tex]M_{NO}](https://tex.z-dn.net/?f=W_%7B1%7D%3D%2090.0%20lb%3D%2040823.3%20grams%3C%2Fp%3E%3Cp%3EWeight%20of%20full%20cylinder%5Btex%5DW_%7B2%7D%20%3D%20116.5%20lb%3D%2052843.511%20grams%3C%2Fp%3E%3Cp%3EThe%20critical%20temperature%20%3D%20287%20K%3C%2Fp%3E%3Cp%3EThe%20critical%20pressure%2054.3%20L%3C%2Fp%3E%3Cp%3EMolar%20mass%20of%20nitric%20acid%20%3D%20%5Btex%5DM_%7BNO%7D)
= 30.01 g/mol
Number of moles nitric acid = 
=?
The mass of nitric acid in the cylinder = 
Number of moles of nitric acid =
Therefore, number of moles nitric acid in the cylinder is 400.539g/mol.
Answer:
2.0000 g
Explanation:
It will show the number out to the 4th decimal place. Exactly 2 g will be displayed as 2.0000 g.
Answer:
B,C,D
Explanation:
The yield of CCl4 depends on the amount of CH4 in a 1:1 ratio. The amount of Cl2 is twice that of CH4 hence some must be left over. To ensure that all the Cl2 is used up, more CH4 must added to the system.
Answer:
Solution of isopropanol is 10.25 molal
Explanation:
615 g of isopropanol (C3H7OH) per liter
We gave the information that 615 g of solute (isopropanol) are contained in 1L of water. We need to find out the mass of solvent, so we use density.
Density of water 1g/mL → Density = Mass of water / 1000 mL of water
Notice we converted the L to mL
Mass of water = 1000 g (which is the same to say 1kg)
Molality are the moles of solute in 1kg of solvent, so let's convert the moles of isopropanol → 615 g . 1mol / 60g = 10.25 moles
Molality (mol/kg) = 10.25 moles / 1kg = 10.25 m
