<span>Answer</span>=.000978802802moles H2SO4
How I Got My Answer
<span>Molar mass
</span>H2SO4= 98.079g/mol
What I have
.0960g H2SO4
Equation
.0960g*1mol/98.079g= .000978802802mol H2SO4
Answer:
<em>The pKa is 13.0.</em>
Explanation:
pKa + pKb = 14
Given, Kb of trimethylamine = 6.3 × 
pKb = - log (6.3 ×
)
= 1.0
⇒ pKa = 14 - pKb = 14 - 1.0
<u>pKa = 13.0</u>
<em><u></u></em>
<em>Check: For most weak acids, pKa ranges from 2 to 13.</em>
<h2>The isotopes of an element all have the same __(atomic, mass) __number, but they have different __(atomic,mass)__numbers.</h2>
Explanation:
The isotopes of an element all have the same __atomic number __, but they have different __mass __numbers.
The isotopes have same atomic number that is :
- Same number of electrons
- Same number of protons
- same electronic configuration
- same valence electrons
- same valency
- same symbol
The isotopes have different mass number that is :
They differ in number of neutrons .
For example : Isotopes of hydrogen are : H₁¹ , H₁² , H₁³
isotopes of Oxygen is : O¹⁶ , O¹⁷, O¹⁸
Answer:
Explanation:
<u>1) Data:</u>
a) Hypochlorous acid = HClO
b) [HClO} = 0.015
c) pH = 4.64
d) pKa = ?
<u>2) Strategy:</u>
With the pH calculate [H₃O⁺], then use the equilibrium equation to calculate the equilibrium constant, Ka, and finally calculate pKa from the definition.
<u>3) Solution:</u>
a) pH
b) Equilibrium equation: HClO (aq) ⇄ ClO⁻ (aq) + H₃O⁺ (aq)
c) Equilibrium constant: Ka = [ClO⁻] [H₃O⁺] / [HClO]
d) From the stoichiometry: [CLO⁻] = [H₃O⁺] = 2.29 × 10 ⁻⁵ M
e) By substitution: Ka = (2.29 × 10 ⁻⁵ M)² / 0.015M = 3.50 × 10⁻⁸ M
f) By definition: pKa = - log Ka = - log (3.50 × 10 ⁻⁸) = 7.46