Answer:
In 12.6g of 
there are 0.29 moles of and 
molecules of
Explanation:
First you should find the molar mass of the :
Then you should write the conversion factor using the molar mass:
So, there are 0.29 moles of in 12.6g of .
Finally to find the number of molecules, you should use the Avogadro´s number:
There are moles of in 12.6g of
The reason for this is because nonmetals, have close to fulfilling an octet and need to gain few more electrons to do this, not to lose more. Nonmetals, because of the fact they need only few more electrons to satisfy their octet they would receive or share electrons to do this.
The property that nonmetals have are that they are very electronegative, they possess a strong affinity to pull electron density closer, because they possess fewer electron shells and possess even protons this allows for this.
Answer:
Explanation:
Hello,
In this case, considering that the safe temperature may be computed via the ideal gas law as we now the pressure, mass and volume via the dimensions:
The pressure in atm is:
And the moles considering the mass and molar mass (66 g/mol) of dinitrogen difluoride (N₂F₂):
In sich a way, by applying the ideal gas equation, which is not the best assumption but could work as an approximation due to the high temperature, the temperature, with three significant figures, will be:
Best regards.
To convert grams to atoms, we first need to find the moles and then multiply by Avogadro's constant.
0.1310 g * (1 mol/22.99 g) * (6.022*10^23 atom/1 mol) = 3.431 *10^21 atoms.
Your compound is
.
Remember that the oxidation numbers in a neutral compound must add up to zero. Cl has an oxidation number of -1 because it is a halogen K has an oxidation number of +1 because it is an alkali metal, which exhibits an oxidation state of +1 in compounds.
Since you have 6 atoms of Cl, you have -1(6) = -6 for the Cl. Since you 2 atoms of K, you have +1(2) = +2 for the K. The oxidation number of Pt must make all the oxidation numbers add up to zero:
+2 + (-6) + oxidation number of Pt = 0
-4 + oxidation number of Pt = 0
Oxidation number of Pt = 4
