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2 years ago

How many grams of nitrogen are in a sample of Al(NO3)3 that contains 364.0 g of aluminum? Answer: ________ grams of nitrogen.

Chemistry

1 answer:

saw5 [17]2 years ago

7 0

<u>Answer:</u> The mass of nitrogen that is present for given amount of aluminium is 566.22 g.

<u>Explanation: </u>

We are given:

Mass of aluminium = 364 grams

The chemical formula of aluminium nitrate is $Al(NO_3)_3$

Molar mass of nitrogen = 14 g/mol

Molar mass of aluminium = 27 g/mol

In 1 mole of aluminium nitrate, 27 grams of aluminium is combining with 42 grams of nitrogen.

So, 364 grams of aluminium will combine with = $\frac{42}{27}\times 364=566.22g$ of nitrogen.

Hence, the mass of nitrogen that is present for given amount of aluminium is 566.22 g.

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