How many grams of nitrogen are in a sample of Al(NO3)3 that contains 364.0 g of aluminum? Answer: ________ grams of nitrogen.

Chemistry

1 answer:

saw5 [17]2 years ago

7 0

<u>Answer:</u> The mass of nitrogen that is present for given amount of aluminium is 566.22 g.

<u>Explanation: </u>

We are given:

Mass of aluminium = 364 grams

The chemical formula of aluminium nitrate is $Al(NO_3)_3$

Molar mass of nitrogen = 14 g/mol

Molar mass of aluminium = 27 g/mol

In 1 mole of aluminium nitrate, 27 grams of aluminium is combining with 42 grams of nitrogen.

So, 364 grams of aluminium will combine with = $\frac{42}{27}\times 364=566.22g$ of nitrogen.

Hence, the mass of nitrogen that is present for given amount of aluminium is 566.22 g.

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Brilliant_brown [7]

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Eugenol is a molecule that contains the phenolic functional group. Which option properly identifies the phenol in eugenol

givi [52]

Answer:

Explanation:

Hello,

Among the options given on the attached document, since phenolic functional group is characterized by a benzene ring bonded with a hydroxyl group (C₆H₅OH) we can see that the first option correctly points out such description. Thus, answer is on the second attached picture. Other options are related with other sections found in eugenol that are not phenolic.

Best regards.