Answer:
Explanation:
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In this case, since we have grams of iron (III) oxide whose molar mass is 159.69 g/mol are able to compute the produced grams of iron by using its atomic mass that is 55.845 g/mol and their 2:4 molar ratio in the chemical reaction:
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Answer: Option (b) is the correct answer.
Explanation:
The energy necessary to remove an electron from a gaseous atom or ion is known as ionization energy.
This means that smaller is the size of an atom more amount of energy has to be supplied to it in order to remove the valence electron. This is because in small atom or element there will be strong force of attraction between the nucleus and electrons.
So, high amount of energy has to be supplied to remove the valence electrons.
As electronic configuration of helium is . So, due to completely filled valence shell it is more stable in nature.
As a result, we need to provide very high amount of energy to remove an electron from a helium atom.
Thus, we can conclude that out of the given options helium element would the first ionization energy of the atom be higher than that of the diatomic molecule.
Mass of potassium hydrogen pthalate KHP is 0.4856 g, its molar mass is 204.22 g/mol, number of moles of KHP can be calculated as follows:
Here, m is mass and M is molar mass, putting the values,
This will be number of moles of NaOH at equivalent point.
Detailed calculations:
Molarity is defined as number of moles in 1 L of solution, for 250 mL of solution, molarity will be:
For 25 mL, apply dilution law as follows:
Putting the values,
On rearranging,
Convert molarity into number of moles,
At equivalent point, number of moles of KHP will be equal to NaOH, thus, number of moles of NaOH will be 0.00237 mol.
Calculation for molarity:
Volume of NaOH is 18.75 mL, thus, molarity can be calculated as follows:
Putting the values,
Therefore, molarity of NaOH is 0.1264 M