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damaskus [11]
1 year ago
14

A student titrated 25.0 cm3 portions of dilute sulfuric acid with a 0.105 mol/dm3 sodium hydroxide solution.The equation for the

reaction is: 2 NaOH + H2SO4 ⟶ Na2SO4 + 2 H2O Calculate the concentration of the sulfuric acid in mol/dm3 Use only the student's concordant results.
Chemistry
1 answer:
Rzqust [24]1 year ago
7 0

Answer:

This question is incomplete

Explanation:

This question is incomplete as the volume of the base that was used during the titration was not provided. However, the completed question is in the attachment below.

The formula to be used here is CₐVₐ/CbVb = nₐ/nb

where Cₐ is the concentration of the acid = unknown

Vₐ is the volume of the acid used = 25 cm³ (as seen in the question)

Cb is the concentration of the base = 0.105 mol/dm³ (as seen in the question)

Vb is the volume of the base = 22.13 cm³ (22.1 + 22.15 + 22.15/3)

nₐ is the number of moles of acid = 1 (from the chemical equation)

nb is the number of moles of base = 2 (from the chemical equation)

Note that the Vb was based on the concordant results (values within the range of 0.1 cm³ of each other on the table) of the student

Cₐ x 25/0.105 x 22.13 = 1/2

Cₐ x 25 x 2 = 0.105 x 22.13 x 1

Cₐ x 50 = 0.105 x 22.13

Cₐ = 0.105 x 22.13/50

Cₐ = 0.047  mol/dm³

The concentration of the sulfuric acid is 0.047  mol/dm³

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A compound that contains only carbon, hydrogen, and oxygen is 48.64% C and 8.16% H by mass. What is the empirical formula of thi
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Answer:

The empirical formula of this substance is:

C_3H_6O_2

Explanation:

To find the empirical formula of this substance we need the molecular weight of the elements Carbon, Hydrogen and Oxygen, we can find this information in the periodic table:

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- H: 1.00 g/mol

- O: 15.99 g/mol

With the information in this exercise we can suppose in 100 g of the substance we have:

C: 48.64 g

H: 8.16 g

O: 43.2 g (100 g - 48.64g - 8.16g= 43.2 g)

Now, we need to divide these grams by the molecular weight:

C=\frac{48.64g}{12.01 g/mol} =4.05 mol\\H=\frac{8.16g}{1.00g/mol}= 8.16 mol\\O=\frac{43.2g}{15.99 g/mol} = 2.70 mol

We need to divide these results by the minor result, in this case O=2.70 mol

C=\frac{4.05mol}{2.70mol}= 1.5\\H= \frac{8.16mol}{2.70 mol} = 3.02 \\O=\frac{2.70mol}{2.70mol} = 1

We need to find integer numbers to find the empirical formula, for this reason we multiply by 2:

C= 1.5*2=3\\H= 3.02*2= 6.04 \\O= 1*2=2

This numbers are very close to integer numbers, so we can find the empirical formula as  subscripts in the chemical formula:

C_3H_6O_2

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2 years ago
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Answer:

There are  

17.01

Explanation:

The chemical formula for calcium phosphate is  

Ca

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(PO

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Glucose and amino acids are reabsorbed from the glomerular filtrate by the __________.
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Answer:

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Explanation:

Glomerular filtration is the regulator of the excretion of metabolites and toxic molecules or not necessary for our body. That is why if the amino acid values ​​are high as well as those of glucose in urine, we will be facing a pathology.

If glucose is increased, it is because there is a glycemic peak in blood volume, hence possible diabetes.

And if the amino acids are increased, we could be facing an autoimmune or proteolytic pathology where a large amount of body proteins such as muscle proteins would be breaking down and releasing the amino acids that make it up, this phenomenon usually appears in those people who suffer from rhabdomyolysis in expenses very intense energy sources not appropriate.

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7 0
2 years ago
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