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alekssr [168]
2 years ago
15

Approximately how many moles of Al3+ are reduced when 0.1 faraday of charge passes through a cell during the production of Al? (

Note: Assume there is excess Al3+ available and that Al3+ is reduced to Al metal only.)
A. 0.033 molB. 0.050 molC. 0.067 molD. 0.10 mol
Chemistry
1 answer:
Natali [406]2 years ago
6 0

Answer:

0.033 mol

Explanation:

1 faraday is require to  1 mol of electron

0.1 faraday is required for 0.1 mol of electron

3 mol of electron is required for 1 mole Al3+ to Al

0.1 mole of electron will therefore need ( 0.1 mol × 1 mol ) / 3 mol = 0.033 mol

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How much heat is absorbed/released when 25.00 g of NH3(g) reacts in the presence of excess O2(g) to produce NO(g) and H2O(l) acc
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Answer:

429.4 kJ are absorbed in the endothermic reaction.

Explanation:

The balanced chemical equation tells us that 1168 kJ of heat are absorbed in the reaction when 4 mol of NH₃ (g) react with 5 mol O₂ (g).

So what we need is to calculates how many moles represent 25 g NH₃(g) and calculate the heat absorbed. (NH₃ is the limiting reagent)

Molar Mass NH₃  = 17.03 g/mol

mol NH₃ = 25.00 g/ 17.03 g/mol = 1.47 mol

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2 years ago
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A. gravity (of any planet/star/celestial body around )

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2 years ago
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Citric acid is a naturally occurring compound. what orbitals are used to form each indicated bond? be sure to answer all parts.
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Answer : The orbitals that are used to form each indicated bond in citric acid is given below as per the attachment.

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Answer 2) π Bond a: C has π orbitals and  O also has π  orbitals.

Explanation : The pi-bond at the 'a'position has carbon and oxygen atoms which undergoes pi-bond formation. And has pi orbitals of oxygen and carbon involved in the bonding process.

Answer 3) Bond b: O sp^{3}  H has only S orbital involved in bonding.

Explanation : The bonding at 'b' position involves oxygen and hydrogen atoms in it. It has sp^{3} hybridized orbitals and S orbital of hydrogen involved in the bonding.

Answer 4) Bond c:   C sp^{3} O sp^{3}

Explanation : The bonding involved at 'c' position has carbon and oxygen atoms involved in it. Both the atoms involves the orbitals of sp^{3} hybridized bonds.

Answer 5) Bond d:   C sp^{3}  C sp^{3}

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Answer 6) Bond e:  C1 containing O sp^{2}    C2 sp^{3}

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2 years ago
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