Answer:
For dispensing, weigh it out.
Yes, a different solvent such as ethanol could be used.
Explanation:
Besides using various methods for melting the <em>tert</em>-butanol in order to pour it out and measure a given volume, the <em>tert</em>-butanol could be weighed out in a beaker using a scale. Depending on the temperature of the laboratory, the <em>tert</em>-butanol could be a solid or a liquid/solid mixture.
In general, a different solvent such as ethanol could be used in place of <em>tert</em>-butanol as long as the solvent is a low molecular weight alcohol.
Answer:
C. 2.000 M C6H12O6
Explanation:
Let us obtain the molarity of the solution.
Molar Mass of C6H12O6 = (12x6) + (12x1) + (16x6) = 72 + 12 + 96 = 180g/mol
Mass of C6H12O6 = 180g
Number of mole = Mass /Molar Mass
Number of mole of C6H12O6 = 180/180 = 1mole
Volume = 500mL = 500/1000 = 0.5L
Molarity = mole /Volume
Molarity = 1/0.5
Molarity = 2M
So the solution will be best labelled as 2M C6H12O6
First situation:
IV: soda, gatorade, orange juice, and water
DV: state of IV listed above
Control: freezer, and ice tray
Second Situation:
IV: laundry detergent, water
DV: result of the squares after being washed
Control: chocolate, type of cloth, squares of cloth
Third Situation:
IV: Water used, pea plant
DV: growth of pea plant
Control: pots and amount of water plant gets each day
The mass of iron block is 500 g. The amount of energy required to melt the iron block needs to be calculated. Melting means conversion of solid to liquid thus, heat of fusion is used which is 247 J/g.
From heat of fusion, 247 J of energy is released by melting 1 g of iron block. Thus, the amount of heat released by melting 500 g of iron rod will be:
H= 247 J/g× 500 g=1.23×10^{5}
Hence, option B is correct.
Answer:6.719Litres of Cl2 gas.
Explanation:According to eqn of rxn
2Na +Cl2=2NaCl
P=689torr=689/760=0.91atm
T=39°C+273=312K
according to stoichiometry of the reaction,1Moles of Cl2 gives 2moles of NaCl
But 28g of NaCl was given,we have to convert this to moles by using the relation, n=mass/MW
MW of NaCl=23+35.5=58.5g/mol
n=28g(mass given of NaCl)/58.5
n=0.479moles of NaCl
Going back to the reaction,
if 1moles of Cl2 produces 2moles of NaCl
x moles of Cl2 will give 0.479moles of NaCl.
x=0.479*1/2
x=0.239moles of Cl2.
To find the volume, we use ideal ggas eqn,PV=nRT
V=nRT/P
V=0.239*0.082*312/0.91
V=6.719Litres
