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Olin [163]
2 years ago
11

The beta oxidation pathway degrades activated fatty acids (acyl-CoA) to acetyl-CoA, which then enters the citric acid cycle. Add

itional enzymes are required to oxidize unsaturated, odd-chain, long-chain, and branched fatty acids.
Which of the following statements are true?

a.A 14-carbon monounsaturated fatty acid with cis configuration yields more ATP than a 14-carbon saturated fatty acid.
b.Enoyl-CoA isomerase, an enzyme that converts cis double bonds to trans double bonds in fatty acid metabolism, bypasses a step that reduces Q, resulting in a higher ATP yield.
c.Even-chain saturated fatty acids are oxidized to acetyl-CoA in the beta oxidation pathway.
d.Complete catabolism of the three-carbon remnant of a 15-carbon fatty acid requires some citric acid cycle enzymes.
e.Trans double bonds in unsaturated fatty acids are not recognized by beta oxidation enzymes.
f.The final round of beta oxidation for a 13-carbon saturated fatty acid yields acetyl-CoA and propionyl-CoA, a three-carbon fragment.
Chemistry
2 answers:
Xelga [282]2 years ago
7 0

Answer:

b) Enoyl CoA isomerase an enzyme that converts cis double bonds to trans double bonds in fatty acid metabolism,bypasses a step that reduces Q,resulting in the higher ATP yield.

c) Even chain fatty acids are oxidized to acetyl CoA in the beta oxidation pathway.

f) The final round of beta oxidation for a 13 carbon saturated fatty acid yields acetyl CoA and propionyl CoA, a three carbon fragment

Explanation:

Beta Oxidation pathway is a pathway that shows the process whereby molecules of fatty acids are broken down into smaller units that undergoes or passes through the process of oxidation in other to produce energy. Beta Oxidation Pathway takes place in the cytosol of prokaryotic organisms or in the mitochondria of eukaryotic organisms.

The end product of Beta Oxidation is Acetyl-CoA and Propionyl-CoA, a three-carbon fragment.

BabaBlast [244]2 years ago
3 0

Answer:

The correct statements are given below

Explanation:

b Enoyl CoA isomerase an enzyme that converts cis double bonds to trans double bonds in fatty acid metabolism,bypasses a step that reduces Q,resulting in the higher ATP yield.

c Even chain fatty acids are oxidized to acetyl CoA in the beta oxidation pathway.

f The final round of beta oxidation foe a 13 carbon saturated fatty acid yields acetyl CoA and propionyl CoA a three carbon fragment.

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For double-helix formation, change in Gibbs free energy, ΔG, can be measured to be −54 kJ⋅mol−1 (−13 kcal⋅mol−1) at pH 7.0 in 1
77julia77 [94]

Answer:

Explanation:

Entropy change in the system : --

ΔG =   −54 kJ⋅mol−1 (−13 kcal⋅mol−1)  =   −54 kJ⋅mol−1 (−13 x 4.2  kJ⋅mol−1)

= - 108.6  KJ / mol

ΔH =  -251 kJ/mol (-60 kcal/mol) =  -251 kJ/mol (-60 x 4.2  kJ/mol)

= - 503  KJ / mol

ΔG = ΔH - TΔS

ΔS = ( ΔH - ΔG ) / T

=  - 503 + 108.6 / ( 273 + 25 ) KJ / mol k⁻¹

= - 1323.48 J / mol k⁻¹

Entropy change in the surrounding

+ 1323.48 J / mol k⁻¹

7 0
2 years ago
Enter the chemical equation 2H+(aq)+S2−(aq)→H2S(g). Express your answer as a chemical equation.
amm1812

Answer : The complete chemical equation is,

2H^+(aq)+S^{2-}(aq)\rightarrow H_2S(aq)

Explanation :

As we know that, in a chemical equation the reacting species present on left side and the product formed present on right side and a right arrow inserted between the reactants and product that show a chemical reaction taking place.

In the chemical reaction, the phases of the substances are also included and subscripts and superscripts are also used for the numbers.

For the given chemical reaction, the balanced chemical equation including the phases, is given by:

2H^+(aq)+S^{2-}(aq)\rightarrow H_2S(aq)

4 0
2 years ago
Read 2 more answers
The pOH of a solution is 6.0. Which statement is correct? Use p O H equals negative logarithm StartBracket upper O upper H super
Katen [24]

Answer:

The pH of the solution is 8.

Explanation:

To which options are correct, let us determine the concentration of the hydroxide ion, [OH-] and the pH of the solution. This is illustrated below:

1. The concentration of the hydroxide ion, [OH-] can be obtained as follow:

pOH = –Log [OH-]

pOH = 6

6 = –Log [OH-]

–6 = Log [OH-]

[OH-] = Antilog (–6)

[OH-] = 1x10^–6 mol/L

2. The pH of the solution can be obtained as follow:

pH + pOH = 14

pOH = 6

pH + 6 = 14

pH = 14 – 6

pH = 8.

From the calculations made above,

[OH-] = 1x10^–6 mol/L

pH = 8.

Therefore, the correct answer is:

The pH of the solution is 8

3 0
2 years ago
A mixture of Na2CO3 and MgCO3 of mass 7.63 g is reacted with an excess of hydrochloric acid. The CO2 gas generated occupies a vo
Svetlanka [38]

Answer:

58.6 % by mass of Na₂CO₃

Explanation:

This is the reaction:

Na₂CO₃  +  MgCO₃ +  4HCl  →  MgCl₂  +  2NaCl  + 2CO₂  +  2H₂O

Let's find out the moles of CO₂ produced, by the Ideal Gases Law

1.24 atm . 1.67 L = n . 0.082 . 299K

(1.24 atm . 1.67 L / 0.082 . 299K) = n

0.0844 moles = n

Ratio is 2:1, so 2 moles of dioxide were produced by 1 mol of sodium carbonate. Let's make a rule of three:

2 moles of CO₂ were produced by 1 mol of Na₂CO₃

Then, 0.0844 moles of Co₂ would beeen produced by (0.0844 .1)/2  = 0.0422 moles of Na₂CO₃.

Let's convert this moles into mass (mol . molar mass)

0.0422 mol . 106 g/mol = 4.47 g

Finally we can know the mass percent of sodium carbonate in the mixture

(Mass of compound /Total mass) . 100 → (4.47 g / 7.63g) . 100 = 58.6 %

3 0
1 year ago
The recommended daily intake of potassium (K) is 4.725 grams. Assuming that every raisin contains 3.677 milligrams of K, how man
Pani-rosa [81]
3.677mg =0,003677g \ \ \ \ \ \ \ \ \Rightarrow \ \ \ \ \ \ \ 1 \ raisin\\ 4,725g \ \ \ \ \ \ \ \ \ \ \ \ \Rightarrow \ \ \ \ \ \ \ \ x\\\\ x=\frac{4,725g*1}{ 0,003677g}\approx 1285 \ raisins
3 0
2 years ago
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