Answer:
8
Explanation:
To solve this question, we just need to put the new number into the equation. If [A] remain constant then that mean [A2]= [A1]. If B doubled, then that mean [B2]= 2[B2]. To find what factor does the rate of reaction increases, we need to divide the first reaction rate with the second. The calculation will be:
rate2/rate1= k[A2][B2]³ / k[A1][B1]³
rate2/rate1= [A1][2B1]³ / [A1][B1]³
rate2/rate1= A1*8B1³ / A1*B1³
rate2/rate1= 8/1= 8
The rate of reaction will be 8 times faster.
<h2>The answers are

and

</h2>
Explanation:
Given -
a) The molecular formula of ethylene glycol -

∴ The empirical formula of ethylene glycol will be -

Given -
b) The molecular formula of per-oxo-disulfuric acid (a compound used in bleaching agents) -

∴ The empirical formula of per-oxo-disulfuric acid will be -

Hence, the answers are
and
.
Answer: The empirical formula of the compound is 
Explanation:
Empirical formula is defined formula which is simplest integer ratio of number of atoms of different elements present in the compound.
Percentage of iron in a compound = 36.76 %
Percentage of sulfur in a compound = 21.11 %
Percentage of oxygen in a compound = 42.13 %
Consider in 100 g of the compound:
Mass of iron in 100 g of compound = 36.76 g
Mass of iron in 100 g of compound = 21.11 g
Mass of iron in 100 g of compound = 42.13 g
Now calculate the number of moles each element:
Moles of iron=
Moles of sulfur=
Moles of oxygen=
Divide the moles of each element by the smallest number of moles to calculated the ratio of the elements to each other
For Iron element = 
For sulfur element =
For oxygen element = 
So, the empirical formula of the compound is 
Answer:
Explanation:
An oxidizing accepts an electron and becomes reduced while a reducing agent loses an electron and become oxidized.
Chemical equation:
1) 2 N₂H₄ + N₂O₄ → 3 N₂ + 4 H₂O
2) Hydrazine ( N₂H₄) is being oxidized
Dinitrogen tetroxide N₂O₄ is being reduced
3) The reducing agent is Hydrazine ( N₂H₄) and the oxidizing agent is dinitrogen tetroxide (N₂O₄)