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2 years ago

A solution contains 10.0 g pentane, C5H12, 20.0 g hexane, C6H14, and 10.0 g benzene, C6H6. What is the mole fraction of hexane?

Chemistry

1 answer:

GREYUIT [131]2 years ago

7 0

Answer:

b) 0.47

Explanation:

MwC5H12 = 72.15g/mol

⇒mol C5H12 = (10.0)*(mol/72.15)=0.1386molC5H12

MwC6H14=86.18g/mol

⇒molC6H14=(20.0)*(mol/86.18)=0,232

MwC6H6=78.11g/mol

⇒molC6H6=(10.0)*(mol/78.11)=0.128molC6H6

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No ,8 x 15 is 90,90-4 is 86

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2 years ago

The reaction A + B → 2 C has the rate law rate = k[A][B]³. By what factor does the rate of reaction increase when [A] remains co

lawyer [7]

Answer:

Explanation:

To solve this question, we just need to put the new number into the equation. If [A] remain constant then that mean [A2]= [A1]. If B doubled, then that mean [B2]= 2[B2]. To find what factor does the rate of reaction increases, we need to divide the first reaction rate with the second. The calculation will be:

rate2/rate1= k[A2][B2]³ / k[A1][B1]³

rate2/rate1= [A1][2B1]³ / [A1][B1]³

rate2/rate1= A1*8B1³ / A1*B1³

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The rate of reaction will be 8 times faster.

7 0

2 years ago

What are the empirical formulas of a) ethylene glycol, a radiator antifreeze, molecular formula C2H6O2 b) peroxodisulfuric acid,

Temka [501]

<h2>The answers are $CH_3O$ and $HSO_4$ </h2>

Explanation:

Given -

a) The molecular formula of ethylene glycol -

$C_2H_6O_2$

∴ The empirical formula of ethylene glycol will be -

$CH_3O$

Given -

b) The molecular formula of per-oxo-disulfuric acid (a compound used in bleaching agents) -

$H_2S_2O_8$

∴ The empirical formula of per-oxo-disulfuric acid will be -

$HSO_4$

Hence, the answers are $CH_3O$ and $HSO_4$ .

6 0

2 years ago

What is the empirical formula? A compound is used to treat iron deficiency in people. It contains 36.76% iron, 21.11% sulfur, an

Mandarinka [93]

Answer: The empirical formula of the compound is $Fe_1S_1O_4$

Explanation:

Empirical formula is defined formula which is simplest integer ratio of number of atoms of different elements present in the compound.

Percentage of iron in a compound = 36.76 %

Percentage of sulfur in a compound = 21.11 %

Percentage of oxygen in a compound = 42.13 %

Consider in 100 g of the compound:

Mass of iron in 100 g of compound = 36.76 g

Mass of iron in 100 g of compound = 21.11 g

Mass of iron in 100 g of compound = 42.13 g

Now calculate the number of moles each element:

Moles of iron= $\frac{36.76 g}{55.84 g/mol}=0.658 mol$

Moles of sulfur= $\frac{21.11 g}{32.06 g/mol}=0.658 mol$

Moles of oxygen= $\frac{42.13 g}{16 g/mol}=2.633 mol$

Divide the moles of each element by the smallest number of moles to calculated the ratio of the elements to each other

For Iron element = $\frac{0.658 mol}{0.658 mol}=1$

For sulfur element = $\frac{0.658 mol}{0.658 mol}=1$

For oxygen element = $\frac{2.633 mol}{0.658 mol}=4.001\approx 4$

So, the empirical formula of the compound is $Fe_1S_1O_4$

4 0

2 years ago

Read 2 more answers

Hydrazine (N2H4) and dinitrogen tetroxide (N2O4) form a self-igniting mixture that has been used as a rocket propellant. The rea

Alexxx [7]

Answer:

Explanation:

An oxidizing accepts an electron and becomes reduced while a reducing agent loses an electron and become oxidized.

Chemical equation:

1) 2 N₂H₄ + N₂O₄ → 3 N₂ + 4 H₂O

2) Hydrazine ( N₂H₄) is being oxidized

Dinitrogen tetroxide N₂O₄ is being reduced

3) The reducing agent is Hydrazine ( N₂H₄) and the oxidizing agent is dinitrogen tetroxide (N₂O₄)

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2 years ago