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Temka [501]
1 year ago
12

What is the mass of 2.15 liters of N2 gas at STP?

Chemistry
1 answer:
devlian [24]1 year ago
6 0

Answer:

2.68g

Explanation:

Given parameters:

Volume of gas at STP = 2.15L

Unkown:

Mass of Nitrogen N₂ gas at STP = ?

Solution

To find the mass of the gas at STP, we use the mole concept approach.

In using the mole approach we follow the following procedures:

1. Find the number of moles of gas at STP using the relationship below:

                  Number of moles = \frac{volume occupied}{22.4dm^{3} mol^{-1} }

                         Note: 1L = 1dm³

2. Then using the mole and mass relationship, we can find the mass of the gas using the equation below:

                Mass = number of moles x molar mass

Workings

1.              Number of moles of N₂ = \frac{2.15}{22.4}

                Number of moles of N₂ = 0.096mole

2. Given that the atomic mass of N = 14g

                       Molar mass of N₂ = 2 x 14 = 28gmol⁻¹

Mass = 0.096mol x  28gmol⁻¹ = 2.68g

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g100num [7]

6.28 mol O2 × 2 mol h2 / 1 mol 02 = 12.56 moles h2

8 0
2 years ago
How many moles of tungsten (W,183.85 g/mol) are in 415 grams of tungsten?
ozzi
2.25739773716275. I used a calculator during class today to get this answer, and I am pretty sure it is right, hope it helps. 
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Consider the following incomplete reaction. Mg + 2Y ---> MgCl₂ + H₂ Choose the formula for the missing substance Y.
vesna_86 [32]
It would be B as the answer
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6. Un volumen de 1.0 mL de agua de mar contiene casi 4 x 10-12 g de Au. El volumen total de agua en los océanos es de 1.5 x 1021
Aleks [24]

Answer:

The total amount of Au is $ 2.0\times10^{24}

Explanation:

Given that,

Mass of 1.0 ml of Au m=4\times10^{-2}\ g

Total volume of water in oceans V=1.5\times10^{21}\ L

We need to calculate the volume in ml

Using given volume

V=1.5\times10^{21}\times1000\ mL

V=1.5\times10^{24}\ mL

We need to calculate the total mass of Au  

Using given data

1\ ml\ volume = 4\times10^{-2}\ g

1.5\times10^{24}\ ml=4\times10^{-2}\times1.5\times10^{24}

So, The total mass of Au is 6\times10^{22}\ g

The mass will be in ounce,

Mass=0.035274\times6\times10^{22}

Mass=2.12\times10^{21}\ ounce

The total amount of the Au Will be

Total\ amount=2.12\times10^{21}\times948

Total\ amount=2.0\times10^{24}

Hence, The total amount of Au is $ 2.0\times10^{24}

3 0
1 year ago
What is the mass of 0.921 moles of sulfur dioxide gas (SO2)?
Serhud [2]

Answer:

mass = 58.944 g

Explanation:

Given data:

Number of moles of SO₂ = 0.921 mol

Mass of SO₂ = ?

Solution:

Formula:

Number of moles = mass/ molar mass

First of all we will calculate the molar mass.

SO₂ = 32 + 16×2 = 64 g/mol

Now we will put the values in formula.

Number of moles = mass/ molar mass

0.921 mol = mass /64 g/mol

mass = 0.921 mol × 64 g/mol

mass = 58.944 g

8 0
1 year ago
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