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o-na [289]
2 years ago
7

Consider the reaction below. 2H2O 2H2 + O2 How many moles of hydrogen are produced when 6.28 mol of oxygen form?

Chemistry
1 answer:
g100num [7]2 years ago
8 0

6.28 mol O2 × 2 mol h2 / 1 mol 02 = 12.56 moles h2

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ioda

Answer:

Explanation:

di) number of protons is 12 for all, number of neutrons is 13 for mg- 25 and 14 for mg-26

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You wish to extract an organic compound from an aqueous phase into an organic layer (three to six extractions on a marco scale).
AVprozaik [17]

Answer:

Explanation:

It will be better to use solvents that are lighter than water, because their density has an influence on the miscibility . This will give you a better separation during extraction.

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2 years ago
How are NGC 1427A and U different? How are they the same?
agasfer [191]

Answer:

that looks pretty and also well NGC 1427A has no general shape, so it is an irregular galaxy. U has a bulge in the center and arms, so it is a spiral galaxy. They are similar in the both certain plenty of dust and gas. Both also have active star-forming sites.

3 0
1 year ago
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You might be able to roughly estimate mass in a visual manner, but it could be easy to dismiss the fact that a mole or even a gr
qwelly [4]

The balanced equation is

CO(g) + 2H2 (g) -> CH3OH(l)

Which means, every 2 moles of H2 will react with 1 mole of CO.

Find the number of moles, n = m/Mr

CO = (1.5x10^-6)/(12) = 1.25 x 10^-7 mol

H2 = (6.8x10^-6)/(2) = 3.4 x 10^-6 mol

Since we have a mole ratio of 2 to 1, H2 value will be multipled by 2 as 2 moles of H2 react to 1 mole of CO.

3.4 x 10^-6 x 2 = 6.8 x 10^-6

So obviously we can see that H2 is in excess and only some H2 molecules will be left at the end of the reaction.

6.8 x 10^-6 - 1.25 x 10^-7 = 6.675 x 10^-6 Moles of unreacted H2

To find the molecules of this amount of moles, Multiply it by Avogadros number, 6.02 x 10^23

Because for every mole, there are 6.02 x 10^23 molecules

6.575 x 10^-6 x 6.02 x 10^23 = 3.96 x 10^ 18 Molecules of gas

8 0
2 years ago
Read 2 more answers
How many grams of water are needed to dissolve 27.8 g of ammonium nitrate NH4NO3 in order to prepare a 0.452 m solution?
Vanyuwa [196]

Answer: 770 g water are needed to dissolve 27.8 g of ammonium nitrate NH_4NO_3 in order to prepare a 0.452 m solution

Explanation:

Molality : It is defined as the number of moles of solute present per kg of solvent

Formula used :

Molality=\frac{n\times 1000}{W_s}

where,

n= moles of solute

Moles of NH_4NO_3=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{27.8g}{80.0g/mol}=0.348moles  

W_s = weight of the solvent in g = ?

0.452=\frac{0.348\times 1000}{W_s}

W_s=770g

Thus 770 g water are needed to dissolve 27.8 g of ammonium nitrate NH_4NO_3 in order to prepare a 0.452 m solution

5 0
2 years ago
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