All categories

2 years ago

A scientist measures the speed of sound in a monatomic gas to be 449 m/s at 20∘C. What is the molar mass of this gas?

Chemistry

1 answer:

Ivan2 years ago

7 0

Answer:

The molar mass of the gas is 36.25 g/mol.

Explanation:

To solve this problem, we can use the mathematical relation:

ν = $\sqrt{3RT/M}$

Where, ν is the speed of light in a gas (ν = 449 m/s),

R is the universal gas constant (R = 8.314 J/mol.K),

T is the temperature of the gas in Kelvin (T = 20 °C + 273 = 293 K),

M is the molar mass of the gas in (Kg/mol).

ν = $\sqrt{3RT/M}$

(449 m/s) = √ (3(8.314 J/mol.K) (293 K) / M,

by squaring the two sides:

(449 m/s)² = (3 (8.314 J/mol.K) (293 K)) / M,

∴ M = (3 (8.314 J/mol.K) (293 K) / (449 m/s)² = 7308.006 / 201601 = 0.03625 Kg/mol.

∴ The molar mass of the gas is 36.25 g/mol.

You might be interested in

In the reaction C + O2 → CO2, 18 g of carbon react with oxygen to produce 72 g of carbon dioxide. What mass of oxygen would be n

bulgar [2K]

Molar mass(C)= 12.0 g/mol
Molar mass (O2)=2*16.0=32.0 g/mol
Molar mass (CO2)=44.0 g/mol

18g C*1mol C/12 g C = 1.5 mol C

C + O2 → CO2

from reaction 1 mol 1 mol 1 mol
from problem 1.5 mol 1.5 mol 1.5 mol

1.5 mol O2*32 g O2/1 mol O2 = 48 g O2

In reality this reaction requires only 48 g O2 for 18 g carbon.
And from 18 g carbon you can get only
1.5 mol CO2*44 g CO2/1 mol CO2=66 g CO2
But these problem has 72g CO2. The best that we can think, it is a mix of CO2 and O2.
So to find all amount of O2 that was added for the reaction (probably people who wrote this problem wanted this)
we need (the mix of 72g - mass of carbon 18 g)= 54 g.
So the only answer that is possible is 2.) 54 g.

3 0

2 years ago

Please help i need to do good in this class

ioda

Answer:

Explanation:

di) number of protons is 12 for all, number of neutrons is 13 for mg- 25 and 14 for mg-26

8 0

1 year ago

You prepare a standard by weighing 10.751 mg of compound X into a 100 mL volumetric flask and making to volume. You further dilu

ArbitrLikvidat [17]

Answer:

0.12693 mg/L

Explanation:

First we calculate the concentration of compound X in the standard prior to dilution:

10.751 mg / 100 mL = 0.10751 mg/mL

Then we calculate the concentration of compound X in the standard after dilution:

0.10751 mg/mL * 5 mL / 25 mL = 0.021502 mg/L

Now we calculate the concentration of compound X in the sample, using the known concentration of standard and the given areas:

2582 * 0.021502 mg/L ÷ 4374 = 0.012693 mg/L

Finally we calculate the concentration of X in the sample prior to dilution:

0.012693 mg/L * 50 mL / 5 mL = 0.12693 mg/L

4 0

1 year ago

What quantum numbers specify these subshells? 2S, 6P, and 3D. (The answer is n= and L=)

statuscvo [17]

N = 1
l = from 0 to (n-1)
ml = -1... + 1
ms = 1/2 or -1/2

eg = 2s
n = 2, m = 0, n = 0
s = 1/2, -1/2

hope this help

4 0

1 year ago

What is the yield of uranium from 2.50 kg U3O8?

mr_godi [17]

Answer: Thus the yield of uranium from 2.50 kg $U_3O_8$ is 2.12 kg

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to molecular mass and contains avogadro's number $(6.023\times 10^{23})$ of particles.