1) Percent composition
<span>Na: 13.60%,
N: 8.29%
C: 35.51%
H: 4.77%
O: 37.85%
-------------
100.02%
2) Convert mass percent to molar composition
For that, divide the percent of each element by its atomic mass.
</span>
<span>Na: 13.60 / 22.99 = 0.5916
N: 8.29 / 14.01 = 0.5917
C: 35.51 / 12.01 = 2.9567
H: 4.77 / 1.01 = 4.7228
O: 37.85 / 16.00 = 2.3656
3) Divide each number by the smallest one:
</span>
<span><span>Na: 0.5916 / 0.5916 = 1.0
N: 0.5917 / 0.5916 = 1.0
C: 2.9567 / 0.5916 = 5.0
H: 4.7228 / 0.5916 = 8.0
O: 2.3656</span> / 0.5916 = 4.0
4) State the empirical formula: Na N C5 H8 O4
5) Calculate the mass of the empirical formula:
Multiplicate the number of each atoms times the atomic mass corresponding atomic mass of the atom.
1 * 22.99 + 1 * 14.01 + 5 * 12.01 + 8 * 1.01 + 4 * 16.00 = 169.13
6) Divide the molar mass by the mass of the empirical formula:
169 / 169.13 = 1
7) Conclusion: the molecular formula is Na N C5 H8 O4, so the number of atoms present in the compound formula are:
Na: 1
N: 1
C: 5
N: 8
O: 4
</span>
<h2>The answers are

and

</h2>
Explanation:
Given -
a) The molecular formula of ethylene glycol -

∴ The empirical formula of ethylene glycol will be -

Given -
b) The molecular formula of per-oxo-disulfuric acid (a compound used in bleaching agents) -

∴ The empirical formula of per-oxo-disulfuric acid will be -

Hence, the answers are
and
.
<h3>Answer:</h3>
Option-C: HCl + H₂O → H₃O⁺ + Cl⁻
Explanation:
Bronsted-Lowery concept of Acid and Base defines Acid as that specie which tends to donate H⁺ (Hydrogen Ion) and bases are those species which accepts H⁺ from Acids.
In selected option, HCl is reacting as Acid as it donates H⁺ to water (lowery bronsted base).
Also, the correspong acid is converted into conjugate base (i.e. Cl⁻) and base is converted into conjugate acid (i.e. H₃O⁺)
With the given problem you gave here, I can't answer the question because I need more details. Luckily, I found a similar problem that's provided with a diagram and a table shown in the attached picture.
This test is called the Benedict's test which is used as test for presence of sugars. If the solution contains sugar, like glucose, the solution would turn from blue to red. If not, it would stay blue.
<em>Therefore, the correct results would be that in row 3.</em>