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jasenka [17]
2 years ago
10

Perform the following conversion: 6.1 × 103 K (the surface temperature of the Sun) to °F and °C. Pay attention to the number of

significant figures in this problem. (Enter your answers in scientific notation.)
Chemistry
1 answer:
Keith_Richards [23]2 years ago
5 0

Answer:

\°C=5.8x10^3\°C

\°F=1.1x10^4\°F

Explanation:

Hello,

In this case, for the calculation of the temperature in degree Celsius we subtract 273.15 to the given temperature in kelvins:

\°C=6100-273.15\\\\\°C=5.8x10^3\°C

Next, by applying the following equation we compute it in degree Fahrenheit:

\°F=(5.8x10^{3}*9/5) + 32\\\\\°F=1.1x10^4\°F

Clearly, since the initial unit has two significant figures the computed units also show two significant figures.

Regards.

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7. A gas-filled weather balloon with a volume of 65.0 L is released at sea-level conditions of
Galina-37 [17]

The balloon will reach its maximum volume and it will burst.

Given:

  • A weather balloon at sea level, with gas at 65.0 L volume, 745 Torr pressure, and 25C temperature.
  • When the balloon was taken to an altitude at which temperature was 25C and pressure was 0.066atm its volume expanded.
  • The maximum volume of the weather balloon is 835 L.

To find:

Whether the weather balloon will reach its maximum volume or not.

Solution:

The pressure of the gas in the weather balloon at sea level = P_1=745 torr

1 atm = 760 torr\\P_1=745 torr=\frac{745}{760} torr = 0.980 atm

The volume of the weather balloon at sea level = V_1=65.0L

The temperature of the gas in the weather balloon at sea level:

T_1=25^oC=25+273.15 K=298.15 K

The balloon rises to an altitude.

The pressure of the gas in the weather balloon at the given altitude:

P_2=0.066atm

The volume of the weather balloon at the given altitude = V_2=?

The temperature of the gas in the weather balloon at the given altitude:

T_1=25^oC=25+273.15 K=298.15 K

Using the Combined gas law:

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}\\\frac{0.980 atm\times 65.0L}{298.15 K}=\frac{0.066atm\times V_2}{298.15K}\\V_2=\frac{0.980 atm\times 65.0L\times 298.15K}{0.066atm\times 298.15 K}\\=965L

The maximum volume of the weather balloon= V = 835 L

V < V_2

The volume of the weather balloon at a given altitude is greater than its maximum volume which means the balloon will reach its maximum volume and it will burst.

Learn more about the combined gas law:

brainly.com/question/13154969?referrer=searchResults

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4 0
1 year ago
The molarity of a solution of 5.0 g of kcl in 100. ml of solution is ________.
sdas [7]
Molarity is defined as the number of moles of solute in 1 L of solution 
mass fo KCl in the solution is - 5.0 g
number of moles of KCl - 5.0 g/ 74.5 g/mol  = 0.067 mol
number of moles of KCl in 100 mL - 0.067 mol
therefore number of KCl moles in 1 L - 0.067 / 100 mL x 1000 mL = 0.67 M
molarity of KCl is 0.67 M
7 0
2 years ago
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sertanlavr [38]

Answer:

Explanation:Since the compound X has no net-dipole moment so we can ascertain that this compound is not associated with any polarity.

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So we can propose that compound X must be trans alkene as only in trans compounds the individual bond dipoles cancel each other.

If one isomer of the alkene is trans then the other two isomers may be cis .

Since the two alkenes give the same molecular formula on hydrogenation which means they are quite similar and only slightly different.

The two possibility of cis structures are possible:

in the first way it is possible the one carbon has two chlorine substituents and the carbon has two hydrogens.

Or the other way could be that two  chlorine atoms are present on the two carbon atoms in cis manner that is on the same side and two hydrogens are also present on the different carbon atoms in the same manner.

Kindly refer the attachments for the structure of compounds:

7 0
2 years ago
Your friend looks at a piece of ice and says “Solids, like ice, have a fixed shape because the particles are not moving.” Is you
Alex_Xolod [135]

Answer:

yes

Explanation:

6 0
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Answer:D

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