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2 years ago

Which of the following describes the electron sharing between hydrogen and fluorine?

3 answers:

4 0

Hello
We know both the elements involved in bonding are non-metals and the primary type of bonds involved in non-metals are covalent bonds. Covalent bonds are formed when two atoms share one or more electrons; thus we know that whatever the number of electrons shared, it has to be equal for both. We can eliminate choices A and B.
Next, we understand that it is easier for one atom to be shared among the two, rather than the 7. First, because Hydrogen needs only 1 electron to be stable and would require energy to compensate the remaining 6. Second, electrons are attracted towards the nucleus so it is inefficient to try and share 7 electrons when 1 provides the same amount of stability to Fluorine.
Therefore, the answer is C.

geniusboy [140]2 years ago

3 0

C. if you dont wantt ot read the whole paragraph it is C

Guest1 year ago

0 0

Which statement describes electron sharing between hydrogen and fluorine

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Calculate the daily aluminum production of a 150,000 [A] aluminum cell that operates at a faradaic efficiency of 89%. The cell r

Gala2k [10]

Explanation:

It is known that in one day there are 24 hours. Hence, number of seconds in 24 hours are as follows.

$24 \times 3600 sec$

Hence, total charge passed daily is calculated as follows.

$150,000 \times 24 \times 3600 sec$

And, number of Faraday of charge is as follows.

$\frac{150,000 \times 24 \times 3600 sec}{96500}$

= 134300.52 F

The oxidation state of aluminium in $Al_{2}O_{3}$ is +3.

$Al^{3+} + 3e^{-} \rightarrow Al(s)$

So, if we have to produce 1 mole of Al(s) we need 3 Faraday of charge.

Therefore, from 134300.52 F the moles of Al obtained with 89% efficiency is calculated as follows.

$\frac{134300.52 F}{3} \times \frac{89}{100}$

= 39842.487 mol

or, = $3.9842 \times 10^{4} mol$

Molar mass of Al = 27 g/mol

Therefore, mass in gram will be calculated as follows.

Mass in grams = $3.9842 \times 10^{4} mol \times 27$

= $107.57 \times 10^{4} g$

= 1075.7 kg/day

Thus, we can conclude that the daily aluminum production of given aluminium is 1075.7 kg/day.

8 0

2 years ago

Mr. Rutherford's chemistry class was collecting data in a neutralization study. Each group had 24 test tubes to check each day f

ycow [4]

I’m pretty sure it is A at least that’s what we did at our school to test this

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2 years ago

The human eye is able to detect as little as 2.35 × 10–18 j of green light of wavelength 510 nm. Calculate the minimum number of

Mariulka [41]

Answer:

The minimum number of photons that can be detected by the human eye is 6.03 × 10 ¹⁶ photons.

Explanation:

The energy of one photon of light is related to the wavelength by the equation:

E = h×c/λ

Where, E is the energy of one photon, h is the Planck's constant, c is the speed of light, and λ is the wavelength of the light.

You are given with λ = 510 nm (nanometers), which you must convert to m (meters), to use SI units ⇒ λ = 510 × 10⁻⁹ m.

The physical constansts needed are:

Planck's constant, h = 6.63 × 10⁻³⁴ J.s

Speed of light, in vacuum, c = 3.0 × 10⁻⁸ m/s

Now you can substitute in the formula can compute for the value of E:

E = 6.63×10⁻³⁴ J.s × 3.0 × 10⁻⁸ m/s / (510×10⁻⁹ m) = 0.039 × 10⁻³³ J

Since, that is the energy of one photon of green light, to calculate the number of photons that can be detected by the human eye, you need to divide the amounf of energy the human eye is able to detect, 2.35 × 10⁻¹⁸ J , by the energy of a photon:

number of photons = 2.35×10 ⁻¹⁸J / 0.039 × 10⁻³³ J/ photon

number of photons = 60.3 × 10¹⁵ photons = 6.03 × 10¹⁶photons

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2 years ago

Draw Lewis structures that obey the octet rule for the following species. Assign the formal charge to each central atom.a. POCI3

Mashutka [201]

Answer:

Explanation:

to begin, three steps are highlighted below which are used to write the Lewis structures of the given compounds, viz;

sum the variance of all the atom

use a pair of electrons to form a bond between each pair of bound atoms

lastly arrange the remaining electrons so as to satisfy the rule for hydrogen and the octet rule for the second-row elements.

the image below gives a step by step explanation as to answering this question.

i hope this was helpful, cheers.

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2 years ago

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Anni [7]

Answer: The weight of the products should be the same after he mixes them.

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