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Keith_Richards [23]

2 years ago

7

0.15 gm of metallic oxide was dissolved in 100 ml of 0.1 N H2SO4 and 25.8 ml of 0.095N NaOH were used to neutralise the remainin

g H2SO4.Calculate the equivalent weight of metallic oxide and metal.
Ans: metallic oxide=19.87
metal=11.87

1 answer:

Mila [183]2 years ago

7 0

Answer:

Explanation:

25.8 ml of .095 N NaOH is needed to neutralise the remaining acid

equivalent of NaOH used = 25.8 x .095 / 1000 = .002451 gm equivalent .

acid remaining = .002451 gm equivalent .

acid initially taken = 100 ml of .1 N / 1000 = . 01 gm equivalent

acid reacted with metal = .01 -.002451 = .007549 gm equivalent

This must have reacted with same gram equivalent of metal oxide

.007549 gm equivalent = .15 gm of metal oxide

1 gm equivalent = 19.87 gm

equivalent weight of metal = 19.87 - equivalent weight of oxygen

= 19.87 - 8 = 11.87 .

1

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Explanation:

From the question we are told that

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2 years ago

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2 years ago

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2 years ago

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2 years ago

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joja [24]

Answer:

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4 0

2 years ago

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