Question

0.15 gm of metallic oxide was dissolved in 100 ml of 0.1 N H2SO4 and 25.8 ml of 0.095N NaOH were used to neutralise the remaining H2SO4.Calculate the equivalent weight of metallic oxide and metal.
Ans: metallic oxide=19.87
metal=11.87​

Answer 1

Answer:

Explanation:

25.8 ml of .095 N NaOH is needed to neutralise the remaining acid

equivalent of NaOH used = 25.8 x .095 / 1000 = .002451 gm equivalent .

acid remaining = .002451 gm equivalent .

acid initially taken = 100 ml of .1 N  /  1000  = . 01 gm equivalent

acid reacted with metal = .01  -.002451 = .007549 gm equivalent

This must have reacted with same gram equivalent of metal oxide

.007549  gm equivalent = .15 gm of metal oxide

1 gm equivalent = 19.87 gm

equivalent weight of metal = 19.87 - equivalent weight of oxygen

= 19.87 - 8 = 11.87 .

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