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antoniya [11.8K]

2 years ago

10

A solid sample of a compound and a liquid sample of the same compound are each tested for electrical conductivity. which test co

nclusion indicates that the compound is ionic?

1 answer:

marshall27 [118]2 years ago

8 0

If these are you choices:
(1) Both the solid and the liquid are good conductors.

(2) Both the solid and the liquid are poor conductors.

(3) The solid is a good conductor, and the liquid is a poor conductor.

(4) The solid is a poor conductor, and the liquid is a good conductor.

Then the answer is number 4. This is because ionic compound conducts electricity when it is dissolved in water.

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A mixture of gases containing 0.20 mol of SO2 and 0.20 mol of O2 in a 4.0 L flask reacts to form SO3. If the temperature is 25ºC

diamong [38]

Answer : The pressure in the flask after reaction complete is, 2.4 atm

Explanation :

To calculate the pressure in the flask after reaction is complete we are using ideal gas equation.

$PV=n_TRT\\\\P=(n_1+n_2)\times \frac{RT}{V}$

where,

P = final pressure in the flask = ?

R = gas constant = 0.0821 L.atm/mol.K

T = temperature = $25^oC=273+25=298K$

V = volume = 4.0 L

$n_1$ = moles of $SO_2$ = 0.20 mol

$n_2$ = moles of $O_2$ = 0.20 mol

Now put all the given values in the above expression, we get:

$P=(0.20+0.20)mol\times \frac{(0.0821L.atm/mol.K)\times (298K)}{4.0L}$

$P=2.4atm$

Thus, the pressure in the flask after reaction complete is, 2.4 atm

5 0

2 years ago

A student has two compounds in two separate bottles but with no labels on either one. One is an unbranched alkane, octane, C8H18

Aleks [24]

Answer:

a) both substances are insoluble in water

b) both substances are soluble in ligroin

c) both substances suffer combustion, octane produces more CO₂ than hexene.

d) both substances are less dense than waterl, with hexene having the lowest density.

e) only hexene would react with bromine

f) only hexene would react with permanganate

Explanation:

a) both substances are non-polar and water is polar

b) both substances are non-polar and lingroin is non-polar

c) C₈H₁₈ + 17.5O₂ → 8CO₂ + 9H₂O

C₆H₁₂ + 9O₂ → 6CO₂ + 6H₂O

d) water = 997 kg/m³

ocatne = 703 kg/m³

hexene = 673 kg/m³

e) bromine test is used to detect unsaturations

f) permanganate test is used to detect unsaturations

7 0

2 years ago

Consider two solutions, the first being 50.0 mL of 1.00 M CuSO4 and the second 50.0 mL of 2.00 M KOH. When the two solutions are

kolbaska11 [484]

Explanation:

Molarity of copper sulfate solution = 1.00 M

Volume of the copper sulfate solution = 50.0 mL = 0.050 L

Moles of copper sulfate = n

$1.00M=\frac{n}{0.050 L}$

n = 0.050 L × 1.00 M= 0.050 mol

1 mol of copper sulfate has 1 mol of copper . Then 0.050 mol of copper sulfate has :

$1\times 0.050 mol=0.050 mol$ of copper

a) Mass of 0.050 moles of copper = 0.050 mol × 63.5 g/mol =3.175 g

b) The identity of the compound which formed after the reaction is copper hydroxide.

c) The complete equation for the reaction that occurs when copper sulfate and potassium hydroxide are mixed:

$CuSO_4(aq)+2KOH (aq)\rightarrow Cu(OH)_2(s)+K_2SO_4 (aq)$

d) $CuSO_4(aq)\rightarrow Cu^{2+}(aq) +SO_{4}^{2-}(aq)$ ..[1]

$KOH (aq)\rightarrow 2K^+(aq) +OH^-(aq)$ ..[2]

$Cu^{2+}(aq) +SO_{4}^{2-}(aq)+2K^+(aq) +2OH^-(aq)\rightarrow Cu(OH)_2(s)+SO_{4}^{2-}(aq)+2K^+(aq)$

Common ion both sides are removed. The net ionic equation is given as:

$Cu^{2+}(aq) +2OH^-(aq)\rightarrow Cu(OH)_2(s)(aq)$

e) Volume of solution after mixing of both solution,V= 50 mL + 50ml = 100 mL

Mass of final solution ,m= 1 mL

Density of solution ,d= 1 g/mL (same as pure water)

$m=d\time V=1 g/ml\times 100 mL = 100 g$

Heat capacity of the solution = c = 4.186 J/g°C (same as pure water)

Change in temperature of the solution,ΔT = 27.7 °C- 21.5 °C=6.2°C

$Q=mc\Delta T$

$Q=100 g\times 4.186 J/g ^oC\times 6.2^oC=2595.32 J=2.595 kJ$

Enthalpy of the reaction = ΔH = $\frac{Q}{\text{Moles of copper}}$

ΔH = $\frac{2.595 kJ}{0.050 mol}=51.90 kJ/mol$

The ΔH for the reaction that occurs on mixing is 51.90 kJ/mol.

7 0

2 years ago

A solution contains cr3+ ions. the addition of 0.063 l of 1.50 m naf solution was needed to completely precipitate the chromium

steposvetlana [31]

Cr{3+} + 3 NaF → CrF3 + 3 Na{+} <span>

First calculate the total mols of NaF.

(0.063 L) x (1.50 mol/L NaF) = 0.0945 mol NaF total </span>

Using stoichiometric ratio:

<span>0.0945 mol NaF * (1 mol Cr3+ / 3 mol NaF) * (51.9961 g Cr3+/mol) = 1.6379 g Cr3+</span>

6 0

2 years ago

The equation for the pH of a substance is pH = –log[H+], where H+ is the concentration of hydrogen ions. A basic solution has a

Rzqust [24]

For the basic solution:
11.2 = -log[H+]
[H+] = 6.31 x 10⁻¹²
For the acidic solution:
2.4 = -log[H+]
[H+] = 3.98 x 10⁻³
The difference:
3.98 x 10⁻³ - 6.31 x 10⁻¹²
≈ 4.0 x 10⁻³
The answer is B

3 0

1 year ago

Read 2 more answers