Answer:
The answer to be filled in the respective blanks in question is
3 and 1
Explanation:
So, we know that the formation of cabon-dioxide mole and that of Adenosin-Tri-Phosphate (ATP) moles will be in the ratio of 3:1 i.e., three carbon-di-oxide moles and 1 ATP mole.
Therefore, we can say that one pyruvate mole when passed through citric acid cycle and pyruvate dehydrogenase yields carbon-di-oxide and ATP moles in the ratio 3:1
Answer
- continuous removal of PH3
- adding more of P into the system
Explanation:
In the reaction P4(g)+6H2(g) ⇌ 4PH3(g);
- The effect of temperature on equilibrium has to do with the heat of reaction. Recall that for an endothermic reaction, heat is absorbed in the reaction, and the value of ΔH is positive. Thus, for an endothermic reaction, we can picture heat as being a reactant:
heat+A⇌BΔH=+
- Since the reaction is endothermic reaction, heat is a absorbed. Decreasing the temperature will shift the equilibrium to the left, while increasing the temperature will shift the equilibrium to the right forming more of PH3.
- According to Le Chatelier’s principle, adding additional reactant to a system will shift the equilibrium to the right, towards the side of the products. In the same Way, reducing the concentration of the product will also shift equilibrium to the right continually forming PH3 as it is removed.
Answer:
- <u>259,000 g of chalk.</u>
Explanation:
<u>1) Data:</u>
a) 2000 boxes
b) 175 g / box
c) % yield = 74%
<u>2) Formula: </u>
- % yield = (theoretical yield / actual yield) × 100
<u>3) Solution:</u>
a) Calcualte the actual yield:
- mass of product = 2000 box × 175 g/ box = 350,000 g
b) Solve for the theoretical yield from the % yield formula:
- % yield = (theoretical yield / actual yield) × 100
⇒ theoretical yield = % yield × actual yield / 100
theoretical yield = 74% × 350,000g / 100 = 259,000 g
Empirical formula of a compound gives the proportions of the elements in that compound but it does not define the actual arrangement and number of atoms.
Let the empirical formula of compound be 
.
The ratio of number of moles of C, H and O can be calculated as follows:
Simplifying the ratio,
Thus, the value of x, y and z will be 1, 2 and 1 respectively.
Therefore, the empirical formula will be 
.
