Answer:
The correct answer is option C, that is, ΔS and ΔSsurr for the process H2O (s) ⇒ H2O(l) are equal in magnitude and opposite in sign.
Explanation:
The temperature at which solid state of water get transformed into liquid state is termed as the melting point of 0 °C. It can be shown by the reaction:
H2O (s) ⇒ H2O (l)
The degree of randomness of a molecule is known as entropy. With the transformation of ice into liquid state, there is an increase in randomness. Thus, the value of entropy becomes positive as shown:
Entropy change (ΔSsys) = ΔSproduct - ΔSreactant
= (69.9 - 47.89) J mol/K
= 22.0 J mol/K
Therefore, the value of entropy change is positive.
Now the value of entropy for surrounding ΔSsurr will be,
ΔSsurr = -ΔHfusion/T
= -6012 j/mol/273
= -22.0 J/molK
Hence, the value of ΔSsurr and ΔSsys exhibit same magnitude with opposite sign.
Answer:
Sodium arachidate; Sodium palmitate and Sodium palmitate
Explanation:
Triglycerides are esters of fatty acids with glycerol. In triglycerides, three fatty acid molecules are linked by ester bonds to each of the three carbon atoms in a glycerol molecule. The fatty acids may be same or different fatty acid molecules. Hydrolysis of triglycerides yields the three fatty acid molecules and glycerol.
Saponification is the process by which a base is used to catalyst the hydrolysis of the ester bonds in glycerides. The products of this base-catalyzed hydrolysis of triglycerides are the metallic salts of the three fatty acids and glycerol. The salts of the fatty acids are known as soaps.
For a triglyceride that has the fatty acid chains arachidic acid, palmitic acid and palmitic acid attached to the three backbone carbons glycerol, the saponification of the triglyceride with NaOH will yield the sodium salts or soaps of the three fatty acids as well as glycerol.
Arachidic acid will react with NaOH to yield sodium arachidate.
The two palmitic acid molecules will each react with NaOH to yield sodium palmitate.
Answer:
EMF = -0.17 V
No
Explanation:
For the reaction :
Cd(s) + Fe2+(aq) → Cd2+(aq) + Fe(s)
we will be using the Nersnt equation to calculate Ecell:
Ecell = Eº -0.0592 V/2 ln Q
where Q = ( Fe⁺² )/ (Cd²⁺)
and (Fe²⁺) and (Cd²) are the molar concentration of Fe²⁺ and Cd²⁺
Reduction
Fe²⁺ + 2e⁻ ⇒ Fe(s) Eº red = -0.4400 V
Oxidation
Cd (s) ⇒ Cd²⁺ + 2e⁻ Eº ox = +0.4000 V
Eºcell = Eox + Ered = 0.4000 V + (-0.4400 V) = -0. 0400 V
Ecell = Eº -0.0692 V/2 ln Q = -0.0400 V - 0.0592/2 ln ( 0.80/0.010 ) = -0.17V
No because Eºcell is negative and ΔºG will be positive since
ΔºG = -nFEºcell
Answer:
B
Explanation:
Firstly, we will need to calculate the number of moles. To do this, we make use of the ideal gas equation
PV = nRT
n = PV/RT
The parameters have the following values according to the question:
P = 780mmHg, we convert this to pascal.
760mHG = 101325pa
780mmHg = xpa
x = (780 * 101325)/760 = 103,991 Pa
V= 400ml = 0.4L
T = 135C = 135 + 273.15 = 408.15K
n = ?
R = 8314.463LPa/K.mol
Substituting these values into the equation yields the following:
n = (103991 * 0.4)/(8314.463 * 408.15)
= 0.012 moles
Now we know 1 mole contains 6.02 * 10^23 molecules, hence, 0.012moles will contain = 0.012 * 6.02 * 10^23 = 7.38 * 10^21 molecules
Answer:
46.6 laps
Explanation:
Step 1: Given data
- Length of the lap (l): 1056 ft
- Total distance to be run (d): 15.0 km
Step 2: Convert "l" to km
We will use the conversion factor 1 km = 3280.84 ft.
1056 ft × (1 km / 3280.84 ft) = 0.3219 km
Step 3: Calculate the number of laps that you should run
We will use the following expression.
laps = d/l
laps = 15.0 km/(0.3219 km/lap)
laps = 46.6 laps
