All categories

2 years ago

Chemists use letters of the alphabet as ____ for the elements.

Chemistry

1 answer:

d1i1m1o1n [39]2 years ago

8 0

Answer:

The symbol is the right answer.

Explanation:

The “ Symbol” is the correct answer because chemist uses the letters of the alphabet to denote the element. For instance, the element oxygen is denoted by the letter of the alphabet “O”, the hydrogen is denoted by the letter of alphabet “H”, Boron is denoted by the letter of alphabet “B”, etc. Here these are the examples that use one letter but there are other elements that use more than 1 letter as the symbol. For example, the Chlorine is represented by the Cl.

You might be interested in

A chef wants to make 1 gallon (128 ounces) of a 15% vinegar-to-oil salad dressing. He only has pure vinegar and a mild 4% vinega

noname [10]

Answer:

Pure vinegar: 12.2 ounces, 4% mix salad: 115.8 ounces

Explanation:

The chef wants to male a 15% vinegar-to-oil salad.

If we call:

$v$ the amount of vinegar in the salad

$o$ the amount of oil in the salad

This means that

$\frac{v}{o}=\frac{15}{100}$

In order to get this salad, the chef has to mix:

- Pure vinegar, which has 100% concentration of vinegar

- A 4% vinegar-to-oil salad: this means that the amount of vinegar in this salad is $v=0.04o$ (4% of the amount of oil)

This means that the total amount of vinegar in the final salad will be:

$v'=v+0.04o$ (1a)

Where v is the amount of pure vinegar added and $o$ is the amount of oil in the 4% salad

While the amount of oil needed is $o'=o$

So we have, since the final salad has 15% concentration of vinegar to oil:

$\frac{v+0.04o}{o}=\frac{15}{100}$ (1)

Moreover, we know that the final volume must be 128 ounces, so

$v'+o=128$ (2)

From eq.(2) and (1a) we get

$v+0.04o+o=128\\v=128-1.04o$

Substituting into (1) and solving for $o$ ,

$\frac{128-1.04o+0.04o}{o}=\frac{15}{100}\\100(128-o)=15o\\20(128-o)=3o\\2560-20o=3o\\o=\frac{2560}{23}=111.3$

Therefore the amount of vinegar must be

$v=128-1.04o=128-(1.04)(111.3)=12.2$

So, the amount of each that should be added is:

- Pure vinegar: 12.2 ounces

- 4% vinegar-to-oil mix: $1.04o=(1.04)(111.3)=115.8$ ounces

5 0

2 years ago

What mass of oxygen reacts when 84.9 g of iron is consumed in the following reaction: Fe+O2= Fe2O3

konstantin123 [22]

First we will calculate the number of moles of Iron:
$n = \frac{m}{M}
$ , where n is the number of moles, m is the mass of iron in the reaction and M is the Atomic weight.
$n= \frac{84.9}{55.845} = 1,52$ moles of Iron.
The same number of moles of Oxygen will take part in the reaction.
So $1,52= \frac{mOxygen}{32}$ where 32 is the Atomical Weight of Oxygen (16 x 2).
=> $mOxygen=32*1,52=48,64$ g