Answer:
The hydroxide ions decrease.
Explanation:
I got it right on the quiz. This is what I saw. Read this, "Adding water to an acid or base will change its pH. Water is mostly water molecules so adding water to an acid or base reduces the concentration of ions in the solution. When an acidic solution is diluted with water the concentration of H + ions decreases and the pH of the solution increases towards 7."
Hope this helps! Tell me if this is wrong just incase.
Answer:
The answer to your question is: 0.373 g
Explanation:
Data
mass = ? g
atoms = 3 x 10 ²¹
AM = 74.92 g
Process
1 mol of As ------------------ 6.023 x 10²³ atoms
x ------------------ 3 x 10 ²¹ atoms
x = 4.98 x 10⁻³ moles
1 mol ------------------------ 74.92 g
4.98 x 10⁻³ moles------- x
x = (4.98 x 10⁻³ x 74.92)/1
x = 0.373 g of As
Answer:
The rate of flow of nitrogen into the reactor is 2,470.588 kg/h.
Explanation:
Mole percentage of nitrogen gas = 25 mole%
Mole percentage of hydrogen gas = 75 mole%
Average molecular weight of the mixture:

Rate of flow of the stream = 3000 kg/h
Mass of stream in 1 hour = 3000 kg = 3,000,000 g
Moles of stream :

Moles of nitrogen gas in 352,941.17 moles of stream be x


x = 88,235.294 mol
Mass of 8,823,529.4 mole of nitrogen gas:

The rate of flow of nitrogen into the reactor is 2,470.588 kg/h.
Answer:
The gold gains a total of 2.468 kilo-joules of energy.
Explanation:
Total heat or energy gained by the gold is equal to heat applied and heat required to melt the gold completely.
Total energy = Q+ Q'
Heat of fusion of gold =
Mass of gold melted ,m= 12.5 g
Specific heat of gold ,c= 0.1291 joules/gram °C
Change in temperature = ΔT = 1064°C - 26°C = 1038 °C
Heat of applied to the gold = Q


Total energy = Q+ Q'

= 2,468.82 Joule= 2.468 kilo-Joule
The gold gains a total of 2.468 kilo-joules of energy.
Answer:
2.94x10²² atoms of Cu
Explanation:
We must work with NA to solve this, where NA is the number of Avogadro, number of particles of 1 mol of anything.
Molar mass Cu = 63.55 g/mol
Mass / Molar mass = Mol → 3.11 g / 63.55 g/m = 0.0489 moles
1 mol of Cu has 6.02x10²³ atoms of Cu
0.0489 moles of Cu, will have (0.0489 .NA)/ 1 = 2.94x10²² atoms of Cu