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Norma-Jean [14]
2 years ago
11

The density of silver metal bar is 10.5 g/cm3 and it occupies a volume space of 0.5l. What is its mass in kilograms (kg).

Chemistry
1 answer:
mojhsa [17]2 years ago
4 0

Density is equal to the ratio of mass to the volume.

The mathematical expression is given as:

Density = \frac{mass}{volume}

Density of silver metal bar=10.5 g/cm^{3}

Convert g/cm^{3} into g/L

1 cm^{3} = 0.001 L

Thus, density  = \frac{10.5}{10^{-3}} g/L

= 10.5\times 10^{3}g/L

Volume = 0.5 L

Put the values,

10.5\times 10^{3}g/L= \frac{mass}{0.5 L}

m= 10.5\times 10^{3}g/L\times 0.5 L

=5.25 \times 10^{3}g

Now, convert gram into kg

1 g = 0.001 kg

Therefore, mass in kg=  \frac{5.25 \times 10^{3}}{10^{-3}}

= 5.25 kg

Thus, mass of silver metal bar in kg=5.25 kg



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Mashutka [201]

Answer:

P_H =2.86

c=1.4\times 10^{-4}

Explanation:

first write the equilibrium equaion ,

C_3H_6O_3  ⇄ C_3H_5O_3^{-}  +H^{+}

assuming degree of dissociation \alpha =1/10;

and initial concentraion of C_3H_6O_3 =c;

At equlibrium ;

concentration of C_3H_6O_3 = c-c\alpha

[C_3H_5O_3^{-}  ]= c\alpha

[H^{+}] = c\alpha

K_a = \frac{c\alpha \times c\alpha}{c-c\alpha}

\alpha is very small so 1-\alpha can be neglected

and equation is;

K_a = {c\alpha \times \alpha}

[H^{+}] = c\alpha = \frac{K_a}{\alpha}

P_H =- log[H^{+} ]

P_H =-logK_a + log\alpha

K_a =1.38\times10^{-4}

\alpha = \frac{1}{10}

P_H= 3.86-1

P_H =2.86

composiion ;

c=\frac{1}{\alpha} \times [H^{+}]

[H^{+}] =antilog(-P_H)

[H^{+} ] =0.0014

c=0.0014\times \frac{1}{10}

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6 0
2 years ago
How much heat must be removed from 25.0g of steam at 118.0C in order to form ice at 15C
NemiM [27]

Answer:

-10778.95 J heat must be removed in order to form the ice at 15 °C.

Explanation:

Given data:

mass of steam = 25 g

Initial temperature = 118 °C

Final temperature = 15 °C

Heat released = ?

Solution:

Formula:

q = m . c . ΔT

we know that specific heat of water is 4.186 J/g.°C

ΔT = final temperature - initial temperature

ΔT = 15 °C - 118 °C

ΔT = -103 °C

now we will put the values in formula

q = m . c . ΔT

q = 25 g × 4.186 J/g.°C × -103 °C

q = -10778.95 J

so, -10778.95 J heat must be removed in order to form the ice at 15 °C.

3 0
2 years ago
How many grams of CaF2 are present in 1.25 L of a 0.15 M solution of CaF2? How do I find the grams I am confused on that part?
dybincka [34]

Answer:

Mass = 14.64 g

Explanation:

Given data:

Volume of solution = 1.25 L

Molarity of Solution = 0.15 M

Mass of CaF₂ = ?

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

We will calculate the number of moles of CaF₂ and then determine the mass by using number of moles.

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number of moles of solute = 0.15 M ×  1.25 L

number of moles of solute = 0.1875 mol/L × L

number of moles of solute = 0.1875 mol

Mass in gram:

Mass = number of moles × molar mass

Mass = 0.1875 mol ×78.07 g/mol

Mass = 14.64 g

7 0
2 years ago
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Butoxors [25]

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Answer:

<span>Fluorine (F2)</span>

8 0
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Eva buys a package of food, and the nutrition label says that
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Answer is 74,844 calories

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