Answer is: volume of sodium hydroxide is 500 cm³.
Chemical reaction: H₂S + 2NaOH → Na₂S + 2H₂O.
From chemical reaction: n(H₂S) : n(NaOH) = 1 : 2.
n(NaOH) = 2 ·0.050 mol.
n(NaOH) = 0.1 mol.
V(NaOH) = n(NaOH) ÷ c(NaOH).
V(NaOH) = 0.1 mol ÷ 0.2 mol/dm³.
V(NaOH) = 0.5 dm³.
V(NaOH) = 0.5 dm³ · 1000 cm³/dm³.
V(NaOH) = 500 cm³.
Answer:
MCl₂
Explanation:
The formula for boiling point elevation can be used to find x. The "complete dissociation" means there will be an ion of M and x ions of Cl in the solution. The number of moles of solute will be 30.2 grams divided by the molecular weight of MClx, where x is the variable we're trying to find.
Then the formula for the salt is MCl₂.
Answer:
it would be c
Explanation:
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Answer:
127.0665 amu
Explanation:
Firstly, to answer the question correctly, we need to access the percentage compositions of the iodine and the contaminant iodine. We can do this by placing their individual masses over the total and multiplying by 100%.
We do this as follows. Since the mass of the contaminant iodine is 1.00070g, the mass of the 129I in that particular sample will be 12.3849 - 1.00070 = 11.3842g
The percentage abundances is as follows:
Synthetic radioisotope % = 1.0007/12.3849 * 100% = 8.1%
Since there are only two constituents, the percentage abundance of the 129I would be 100 - 8.1 = 91.9%
Now, we can use these percentages to get the apparent atomic mass. We get this by multiplying the percentage abundance’s by the atomic masses of both and adding together.
That is :
[8.1/100 * 128.9050] + [91.9/100 * 126.9045] = 10.441305 + 116.6252355 = 127.0665 amu
<span>(19.55 mol Au) / ( 1 ) x (196.97 g Au) / ( 1 mol Au) =
19.55 x 196.97 =
3850.76 g Au
I hope this helps you and have a great day!! :)
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