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olganol [36]
1 year ago
5

How many grams of oxygen are in 56 g of c2h2o2?

Chemistry
2 answers:
inessss [21]1 year ago
4 0

<u>Answer:</u> Mass of oxygen atom in given amount of compound is 30.88 grams.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}  ....(1)

Given mass of C_2H_2O_2=56g

Molar mass of C_2H_2O_2=58g/mol

Putting values in above equation, we get:

\text{Moles of }C_2H_2O_2=\frac{56g}{58g/mol}=0.965mol

In 1 mole of C_2H_2O_2, 2 moles of carbon atoms, 2 moles of oxygen atoms and 2 moles of hydrogen atoms.

So, in 0.965 moles of C_2H_2O_2, moles of oxygen atoms will be = \frac{2}{1}\times 0.965=1.93mol

Calculating the mass of oxygen atoms by using equation 1:

Moles of oxygen atoms = 1.93 moles

Molar mass of oxygen atom = 16 g/mol

Putting values in equation 1, we get:

1.93mol=\frac{\text{Mass of oxygen atom}}{16g/mol}\\\\\text{Mass of oxygen atom}=30.88g

Hence, mass of oxygen atom in given amount of compound is 30.88 grams.

jolli1 [7]1 year ago
3 0
First, find percent of oxygen: atom/molecule... there are 2 atoms of Oxygen so: O2/C2H2O2 which is: 32g O2 / 58g C2H2O2 =32/58. 

<span>Next, multiply this by the total mass (56g C2H2O2) and the units will cancel out (g*g/g -> g) leaving you with the mass of Oxygen: </span>

<span>56g C2H2O2 * 32g O2/58g C2H2O2 = 56*32/58= 31g</span>
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