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raketka [301]
2 years ago
7

It is important to know the difference between atoms, ions, and isotopes. Choose all of the correct answers. An atom of oxygen a

nd the ion of oxygen both have 8 protons. Electrons must be removed from a carbon atom to form an isotope. The atomic mass of metals is calculated differently that the atomic mass of nonmetals. As you add or remove neutrons from the nucleus, isotopes are formed. The most massive subatomic particles are electrons. The isotope of carbon and the atom of nitrogen both have 7 protons in the nucleus.
Chemistry
2 answers:
KiRa [710]2 years ago
6 0

Answer : The correct options are,

An atom of oxygen and the ion of oxygen both have 8 protons.

As you add or remove neutrons from the nucleus, isotopes are formed.

Explanation :

Isotope : Isotope is the chemical element in which the number of protons and electrons are same but differ in the number of neutrons. And the atomic mass also different. The atomic number is always same.

  • An atom of oxygen and the ion of oxygen both have 8 protons.

This statement is correct because there is no change in the number of protons only changes in the number of electrons.

  • Electrons must be removed from a carbon atom to form an isotope.

This statement is incorrect because when we remove electrons, the atomic number changed. By changing the atomic number, the element will also changed.

  • The atomic mass of metals is calculated differently that the atomic mass of nonmetals.

this statement is incorrect because there is no different method used for the calculation of the metal and non-metal.

  • As you add or remove neutrons from the nucleus, isotopes are formed.

This statement is correct. Isotope is the chemical element in which the number of protons and electrons are same but differ in the number of neutrons. And the atomic mass also different. The atomic number is always same.

  • The most massive subatomic particles are electrons.

This statement is incorrect because electrons are the lighter subatomic particle as compared to the protons and the neutrons.

  • The isotope of carbon and the atom of nitrogen both have 7 protons in the nucleus.

This statement is incorrect because in the isotope of carbon, the number of neutrons are different but the number of protons are always be 6. The number of protons in the nitrogen atom is 7.

bija089 [108]2 years ago
4 0

The following are true:-

An atom of oxygen and the ion of oxygen both have 8 protons.

As you add or remove neutrons from the nucleus, isotopes are formed.

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How many Mg atoms are present in 170g of Mg
PIT_PIT [208]
In order to calculate the number of atoms, we must first know the number of moles present. And
moles = (mass present) / (molecular mass)
Therefore, the moles of Mg present are
170 / 24 = 7.08
The number of atoms in a mole of substance is given by Avagadro's Number which is 6.02 x 10^23
Since there are 7.08 moles, there are:
7.08 * 6.02*10^23
= 4.26 * 10^24 atoms
8 0
2 years ago
Complete the following radioactive decay problem.<br> 210/84 Po --&gt; 206/82 Pb + ____/____ __
vazorg [7]

₈₄²¹⁰Po ⟶ ₈₂²⁰⁶Pb + _2^4He  

Your equation is:  

₈₄²¹⁰Po ⟶ ₈₂²⁰⁶Pb + ?

It becomes easier to balance the equation if we replace the "?" with an element symbol _<em>x</em>^<em>y</em>Z.  

Then the equation becomes  

₈₄²¹⁰Po ⟶ ₈₂²⁰⁶Pb +_<em>x</em>^<em>y</em>Z

The main point to remember in balancing nuclear equations is that the <em>sums of the superscripts and the subscripts</em> must be the same <em>on each side of the equation</em>.  

Sum of superscripts: 210 = 206 + <em>y</em>, so <em>y</em> =4.  

Sum of subscripts: 84 = 82 + <em>x</em>, so<em> x</em> = 2.

₈₄²¹⁰Po ⟶ ₈₂²⁰⁶Pb + _2^4He

We should recall that _2^4He is an <em>α particl</em>e.

Thus, the equation represents the α decay of polonium-210 to lead-206.

The nuclear equation is  

₈₄²¹⁰Po ⟶ ₈₂²⁰⁶Pb + _2^4He

4 0
2 years ago
Write the balanced molecular and net ionic equation for the reaction that occurs when the contents of the two beakers are added
hram777 [196]

1) hydrochloric acid with nickel:

Balanced molecular equation: Ni(s) + 2HCl(aq) → NiCl₂(aq) + H₂(g).

Ionic equation: Ni(s) + 2H⁺(aq) + 2Cl⁻(aq) → Ni²⁺(aq) + 2Cl⁻(aq) + H₂(g).

Net ionic equation: Ni(s) + 2H⁺(aq) → Ni²⁺(aq) + H₂(g).

Nickel is oxidized from oxidation number 0 (Ni) to oxidation number +2, hydrogen is reduced from oxidation number +1 to oxidation number 0 (H₂).

2) sulfuric acid with iron:

Balanced molecular equation: Fe(s) + H₂SO₄(aq) → FeSO₄(aq) + H₂(g).

Ionic equation: Fe(s) + 2H⁺(aq) + SO₄²⁻(aq) → Fe²⁺(aq) + SO₄²⁻(aq) + H₂(g).

Net ionic equation: Fe(s) + 2H⁺(aq) → Fe²⁺(aq) + H₂.

Iron is oxidized from oxidation number 0 (Fe) to oxidation number +2, hydrogen is reduced from oxidation number +1 to oxidation number 0 (H₂).

3) hydrobromic acid with magnesium :

Balanced molecular equation: Mg(s) + 2HBr(aq) → MgBr₂(aq) + H₂(g).

Ionic equation: Mg(s) + 2H⁺(aq) + 2Br⁻(aq) → Mg²⁺(aq) + 2Br⁻(aq) + H₂(g).

Net ionic equation: Mg(s) + 2H⁺(aq) → Mg²⁺(aq) + H₂(g).

Magnesium is oxidized from oxidation number 0 (Mg) to oxidation number +2, hydrogen is reduced from oxidation number +1 to oxidation number 0 (H₂).

4) acetic acid with zinc:

Balanced molecular equation: Zn(s) + 2CH₃COOH(aq) → (CH₃COO)₂Zn(aq) + H₂(g).

Ionic equation: Zn(s) + 2H⁺(aq) + 2CH₃COO⁻(aq) → Zn²⁺(aq) + 2CH₃COO⁻(aq) + H₂(g).

Net ionic equation: Zn(s) + 2H⁺(aq) → Zn²⁺(aq) + H₂(g).

Zinc is oxidized from oxidation number 0 (Zn) to oxidation number +2 (Zn²⁺), hydrogen is reduced from oxidation number +1 to oxidation number 0 (H₂).

7 0
2 years ago
A piece of silver releases 202.8 J of heat while cooling 65.0 °C. What is the mass of the sample? Silver has a specific heat of
KiRa [710]

Answer: 13 grams

Explanation:

The quantity of heat energy (Q) released from a heated substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Since,

Q = 202.8 Joules

Mass of silver = ?

C = 0.240 J/g °C.

Φ = 65°C

Then, Q = MCΦ

202.8J = M x 0.240 J/g °C x 65°C

202.8J = M x 15.6 J/g

M = (202.8J / 15.6 J/g)

M = 13 g

Thus, the mass of silver is 13 grams

7 0
2 years ago
Choose the thermochemical equation that illustrates ΔH°f for Li2SO4. Choose the thermochemical equation that illustrates ΔH°f fo
Deffense [45]

Answer:

2Li(s) + ⅛S₈(s, rhombic) + 2O₂(g) → Li₂SO₄(s)  

Explanation:

A thermochemical equation must show the formation of 1 mol of a substance from its elements in their most stable state,.

The only equation that meets those conditions is the last one.

A and B are wrong , because they show Li₂SO₄ as a reactant, not a product.

C is wrong because Li⁺ and SO₄²⁻ are not elements.

D is wrong because it shows the formation of 8 mol of Li₂SO₄.

8 0
2 years ago
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