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lukranit [14]
2 years ago
13

Which statement best describes why specific heat capacity is often more useful than heat capacity for scientists when comparing

two materials?
Specific heat capacity is an intensive property and does not depend on sample size.
Specific heat capacity is an extensive property and does not depend on sample size.
Specific heat capacity is an intensive property and depends on the sample size.
Specific heat capacity is an extensive property and depends on the sample size.
Chemistry
2 answers:
zhuklara [117]2 years ago
7 0
<span>Specific heat capacity is an intensive property and does not depend on sample size.</span>
Misha Larkins [42]2 years ago
6 0

The correct option is this: SPECIFIC HEAT CAPACITY IS AN INTENSIVE PROPERTY AND DOES NOT DEPEND ON SAMPLE SIZE.

Generally, all the properties of matters can be divided into two classes, these are intensive and extensive properties. Intensive properties are those properties that are not determined by the quantity of the material that is present or available. Examples of intensive properties are colour, density and specific heat capacity. For instance, whether you have a bucket of water or a cup of water, the quantity does not matter, the colour of water will always remain the same. Extensive properties in contrast, are those properties that depend on the quantity of material that is available. Examples are mass, heat capacity and volume.

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If your lungs were filled with air containing this level of lead, how many lead atoms would be in your lungs? (Assume a total lu
kolbaska11 [484]

Answer:

1.505×10^23 atoms of lead

Explanation:

Volume of lead in the lungs = total volume of lungs = 5.60L

1 mole = 22.4L

5.6L of lead = 5.6/22.4 = 0.25 mole

From Avogadro's law

1 mole of lead contains 6.02×10^23 atoms of lead

0.25 mole of lead = 0.25×6.02×10^23 = 1.505×10^23 atoms of lead

6 0
2 years ago
An electron is on a -2.5 eV energy level. The electron is struck by a 2.5 eV photon. What will most likely happen?
kati45 [8]
The correct answer would be C
5 0
2 years ago
A scientist measures the mass of two liquids before and after combining them. The mass after combining the liquids is less then
Lelu [443]

Answer:

A chemical change occurred and a gas was produced.  

Step-by-step explanation:

If there is no chemical reaction, the <em>Law of Conservation of Mass</em> says that  

Total mass = Mass 1 + Mass 2

However, if the two liquids react and give off a gas, then

Total mass = Mass 1 + Mass 2 + Mass of gas

You are not measuring the mass of the gas, so the mass of the liquids after mixing is less than it was before mixing.

For example, if Liquid 1 was a solution of HCl and Liquid 2 was a solution of Na₂CO₃, they would give off CO₂ on mixing. but you would not be measuring the mass of the CO₂.

4 0
2 years ago
Find the concentration of H+ ions at a pH = 11 and pH = 6. Then divide the concentration of H+ ions at a pH = 11 by the of H+ io
andrew11 [14]

Explanation:

When pH of the solution is 11.

pH=-\log[H^+]

11=-\log[H^+]

[H^+]=1\times 10^{-11} M..(1)

At pH = 11, the concentration of H^+ ions is 1\times 10^{-11} M.

When the pH of the solution is 6.

pH=-\log[H^+]'

6=-\log[H^+]'

[H^+]'=1\times 10^{-6} M..(2)

At pH = 6, the concentration of H^+ ions is 1\times 10^{-6} M.

On dividing (1) by (2).

\frac{[H^+]}{[H^+]'}=\frac{1\times 10^{-11} M}{1\times 10^{-6}}=1\times 10^{-5}

The ratio of hydrogen ions in solution of pH equal to 11 to the solution of pH equal to 6 is 1\times 10^{-5}.

Difference between the H^+ ions at both pH:

1\times 10^{-6} M-1\times 10^{-11} M=9.99\time 10^{-7} M

This means that Hydrogen ions in a solution at pH = 7 has 9.99\time 10^{-7} M ions fewer than in a solution at a pH = 6

6 0
2 years ago
Read 2 more answers
What is the balanced chemical equation for the reaction used to calculate ΔH∘f of SrCO3(s)?
Igoryamba

Answer :

Standard enthalpy of formation : It is defined as the enthalpy change for the reaction that forms one mole of compound from its elements. All the substances in their standard states.

The balanced chemical equation for the reaction is,

Sr(s)+C(s)+\frac{3}{2}O_2(g)\rightarrow SrCO_3(s)

In the balance reaction, Strontium (Sr), Carbon (C) and Strontium carbonate SrCO_3 are in solid state and oxygen is in gaseous state.

5 0
2 years ago
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