<u>Answer:</u> The balanced chemical equation is written below.
<u>Explanation:</u>
Galvanization is defined as the process in which a protective layer of zinc is applied to iron or steel to prevent the metal from rusting.
Zinc prevents the oxidation of iron and acts as a reducing agent in the process.
The half reaction for the process follows:
<u>Oxidation half reaction:</u> 
<u>Reduction half reaction:</u> 
Net chemical equation: 
Hence, the balanced chemical equation is written above.
The second gas is identified as follows
by Graham law formula
let the unknown gas be represented by letter y
=time of effusion of Neon/ time of effusion of y = sqrt (molar mass of neon/molar mass of y)
= 72 sec/ 147 sec = sqrt( 20.18 g/mol/ y g/mol)
square the both side to remove the square root sign
72^2/147^2 = 20.18 g/mol/y g/mol
=0.24 = 20.18g/mol/y g/mol
multiply both side by y g/mol
= 0.24 y g/mol = 20.18g/mol
divide both side by 0.24
y = 84 g/mol
y is therefore Krypton since it is the one with a molar mass of 84 g/mol
Answer:
C₂H₇F₂P
Explanation:
Given parameters:
Composition by mass:
C = 24%
H = 7%
F = 38%
P = 31%
Unknown:
Empirical formula of compound;
Solution :
The empirical formula is the simplest formula of a compound. To solve for this, follow the process below;
C H F P
% composition
by mass 24 7 38 31
Molar mass 12 1 19 31
Number of
moles 24/12 7/1 38/19 31/31
2 7 2 1
Dividing
by the
smallest 2/1 7/1 2/1 1/1
2 7 2 1
Empirical formula C₂H₇F₂P
Answer:
NH₃/NH₄Cl
Explanation:
We can calculate the pH of a buffer using the Henderson-Hasselbalch's equation.
![pH=pKa+log\frac{[base]}{[acid]}](https://tex.z-dn.net/?f=pH%3DpKa%2Blog%5Cfrac%7B%5Bbase%5D%7D%7B%5Bacid%5D%7D)
If the concentration of the acid is equal to that of the base, the pH will be equal to the pKa of the buffer. The optimum range of work of pH is pKa ± 1.
Let's consider the following buffers and their pKa.
- CH₃COONa/CH3COOH (pKa = 4.74)
The optimum buffer is NH₃/NH₄Cl.
Answer:
27.0
Explanation:
Because Mass can neither be created nor be destroyed hence total mass of sample of iodine and tube remain equal as it is sealed.
