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Vladimir [108]
1 year ago
11

Arsenic produces a blue flame when heated. Calcium produces an orange-red flame. Which of these best explains why this differenc

e occurs?
Chemistry
1 answer:
MrMuchimi1 year ago
6 0

Flame colors are produced from the movement of the electrons in the metal ions present in the compounds. When you heat it, the electrons gain energy and can jump into any of the empty orbitals at higher levels Each of these jumps involves a specific amount of energy being released as light energy, and each corresponds to a particular color. As a result of all these jumps, a spectrum of colored lines will be produced. The color you see will be a combination of all these individual colors.

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A substance has a density of 4.5gmL. What is this in kgL? Report your answer with two significant figures.
Ipatiy [6.2K]

Answer:

4.5 kg/L

Explanation:

Density is 4.5g/mL and it means that in 1 mL of volume, the mass contained is 4.5 g.

Let's make a rule of three

1L = 1000 mL

1 mL has a mass of 4.5 g

1000 mL would have 4500 g

Our new density would be 4500 g/L, but we may convert the g to kg

1 kg / 1000 g . 4500 g = 4.5 kg

In conclusion 4.5 g/mL = 4.5 kg/L

7 0
1 year ago
Enter the correct answer for each unit conversion.
Luden [163]

Answer:

50 mm

4 ft

36 ft

250 cm

1 L

Explanation:

Centimeter to  millimeter:

1 cm is equal to 10 mm.

5cm× 10 mm/1 cm

50 mm

Inches to feet conversion:

1 foot is equal to 12 inches.

48 inch ×  1 feet /12 inch

4 feet

Yard to Feet conversion:

1 yard is equal to 3 feet.

12 yd × 3 ft / 1 yd

36 ft

Meter to centimeter:

One meter is equal to 100 cm.

2.5 m × 100 cm / 1m

250 cm

Milliliter to Liter:

One L is equal to 1000 mL.

1000 mL = 1 L

4 0
1 year ago
Read 2 more answers
N2 and H2 are mixed in 14:3 mass ratio. After certain time ammonia was found to be 40% by mol. The mole fraction of N2 at that t
son4ous [18]

Answer : The mole fraction of nitrogen will be 0.4615.


Explanation : When nitrogen (N_{2})and hydrogen (H_{2})are mixed, the mole ratio becomes 1 : 1.5,


Now we know that (H_{2}) is acting as a limiting agent.


So at the time of when 0.4 moles of (NH_{3}) is been formed it requires 0.4 moles of (N_{2}) and 3.4 moles of (H_{2})


So, we find the the remaining (N_{2}) will be 0.6 and

(H_{2}) will be 0.3 mole present in mixture.


So, the mole fraction of (N_{2}) becomes = 0.6 / (0.6 + 0.4 + 0.3) Which becomes = 0.4615

8 0
2 years ago
Read 2 more answers
5. Hydrochloric Acid + Sodium Hydroxide à Sodium<br> Chloride +
erma4kov [3.2K]

HCl Acid + Sodium Hydroxide ----> Sodium  Chloride + water.

<u>Explanation</u>:

  • The reaction between an acid and a base is known as a neutralization reaction. The reaction of an acid with a base to give salt, water and heat is called neutralization.
  • When hydrochloric acid reacts with sodium hydroxide, sodium chloride and water are produced.  

                             HCl + NaOH → NaCl + H2O + Heat

  • The heat evolved in the neutralization reaction raises the temperature of the reaction mixture.    
  • An electro-electrodialysis process (EED) is utilized to create HCl and NaOH from exchange NaCl. NaOH and HCl arrangements with purity higher than 99.9% are acquired. The experimental estimations of the transitions for HCl and NaOH are contrasted and values determined from the incorporation of the Nernst–Planck electro dispersion conditions.
5 0
1 year ago
consider the reaction between sulfite and a metal anion, X2-, to form the metal, X, and thiosulfate: 2 X2-(aq) + 2 SO32- + 3 H2O
Dafna11 [192]

Answer:

E_{red}^{0} for X is -1.20 V

Explanation:

Oxidation: 2\times[X^{2-}(aq.)-2e^{-}\rightarrow X(s)]

reduction: 2SO_{3}^{2-}(aq.)+3H_{2}O(l)+4e^{-}\rightarrow S_{2}O_{3}^{2-}(aq.)+6OH^{-}(aq.)

---------------------------------------------------------------------------------------------------

overall:2X^{2-}(aq.)+2SO_{3}^{2-}(aq.)+3H_{2}O(l)\rightarrow 2X(s)+S_{2}O_{3}^{2-}(aq.)+6OH^{-}(aq.)

So, E_{cell}^{0}=E_{red}^{0}(SO_{3}^{2-}\mid S_{2}O_{3}^{2-})-E_{red}^{0}(X\mid X^{2-})

or, 0.63=-0.57-E_{red}^{0}(X\mid X^{2-})

or, E_{red}^{0}(X\mid X^{2-})= -1.20

So, E_{red}^{0} for X is -1.20 V

8 0
2 years ago
Read 2 more answers
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