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solniwko [45]
2 years ago
7

what is the molarity of a dolution in which 5.6 moles of sodium nitrate is dissolved in water to a final volume of 4.9L

Chemistry
2 answers:
seraphim [82]2 years ago
7 0

Answer:

Molarity of the given solution is 1.14 M

Explanation:

Molarity of a solution = (Number of moles of solutes)/(volume of solution in litre)

Here solute is sodium nitrate and solvent is water.

Total volume of solution is 4.9 L.

So molarity of solution = (5.6 moles)/(4.9 L) = 1.14 M

weqwewe [10]2 years ago
5 0

Molarity of a solution is the moles of solute present in 1 L solution.

Given the moles of sodium nitrate = 5.6 mol

Volume of solution = 4.9 L

Molarity of the solution = \frac{5.6 mol}{4.9 L} = 1.143 mol/L

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A 200.-milliliter sample of CO2(g) is placed in a sealed, rigid cylinder with a movable piston at 296 K and 101.3 kPa. Determine
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Answer:

The final volume of the sample of gas V_{2} = 0.000151 m^{3}

Explanation:

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Final temperature T_{2} = 336 K

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Relation between P , V & T is given by

P_{1} \frac{V_{1} }{T_{1} } = P_{2} \frac{V_{2} }{T_{2} }

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4 0
2 years ago
As Danny was pouring cereal for his breakfast, he noticed that the cereal box says that the cereal contains 5 milligrams of iron
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6 0
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A 108 49in source emits a 633-kev gamma photon and a 606-kev internal-conversion electron from the k shell. what is the binding
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The equilibrium constant, Kc, for the reaction H2 (g) + I2 (g) ⇄ 2HI (g) at 425°C is 54.8. A reaction vessel contains 0.0890 M H
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Answer: The reaction is not at equilibrium and will proceed to make more products to reach equilibrium.

Explanation:  

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_{eq}

K is the constant of a certain reaction when it is in equilibrium, while Q is the reaction  quotient of activities of products and reactants at any stage other than equilibrium of a reaction.

For the given chemical reaction:

H_2(g)+I_2(g)\rightarrow 2HI(g)

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