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2 years ago

An ordered list of chemical substances is shown.

Chemistry

1 answer:

alina1380 [7]2 years ago

8 0

Answer : The correct option is, (C) 2, 4 and 5.

Explanation :

Combustion reaction : It is a type of reaction in which a hydrocarbon react with an oxygen molecule to give carbon dioxide, water as a product.

For example : Methane react with oxygen to give carbon dioxide and water.

$CH_4+2O_2\rightarrow CO_2+2H_2O$

In the given list of chemical substances, $CuO,Cu_2O,Li_2O$ are in oxide form. They can not be both reactant and product of a single combustion reaction.

In the given list, $C_2H_5NH_2$ is the only hydrocarbon which shows a combustion reaction. That means $C_2H_5NH_2$ react with $O_2$ to give $CO_2,H_2O$ and $N_2$ as a product.

The balanced combustion reaction of $C_2H_5NH_2$ is,

$20C_2H_5NH_2+40O_2\rightarrow 40CO_2+7H_2O+10N_2$

Therefore, the correct answer is, (C) 2, 4, and 5.

You might be interested in

How many grams of KClO3 are needed to produce of 4.26 moles of O2? 2 KClO3 2 KCl + 3 O2 a. 348 g b. 136 g c. 174 g d. 522 g e. 7

JulsSmile [24]

Ok so this is what we know :

2KClO3 -> 2KCl + 3O2 (Always check if equation is balanced - in this case it is)
4.26moles
So we know that we have 4.26 moles of oxygen (O2). Now lets look at the ratio between KClO3 and O2.
We see that the ratio is 2:3 meaning that we need 2KClO3 in order to produce 3O2.
Therefore divide 4.26 by 3 and then multiply by 2.
4.26/3 = 1.42
1.42 * 2 = 2.84
Now we know that the molarity of KClO3 is 2.84 moles.
Multiply by R.M.M to find how many grams of KClO3 we have.

R.M.M of KClO3
K- 39
Cl- 35.5
3O- 3 * 16 -> 48
---------------------------
122.5
2.84 * 122.5 = 347.9 grams therefore the answer is (a)
348 grams needed of KClO3 to produce 4.26 moles of O2.
Hope this helps :).

8 0

2 years ago

Read 2 more answers

The information below describes a redox reaction. 3 equations: First: upper C r superscript 3 plus (a q) plus 2 upper C l supers

Marrrta [24]

Answer:

Explanation:

I just took the quiz.

7 0

2 years ago

El cuerpo humano tiene unos 6 billones de células (6,0x1012) y la población de la Tierra es de unos 8 000 millones de personas.

zloy xaker [14]

Answer:

En toda la población del mundo hay 0.0797 moles de células

Explanation:

1.0 mol of cells = 6.022 * 10∧23 cells

X mol of cells = 6.0 * 10∧12 cells

- X is cleared to find out how many moles of cells are in a human body:

X = 6.0 * 10∧12 cells / 6.022 * 10∧23 cells

X = 9,963 * 10∧-12 moles of cells per person

In the world there are 8 * 10∧9 people, how many moles in total will there be?

8 * 10∧9 people * 9,963 * 10∧-12 moles of cells per person =

0.0797 moles of molecules in the entire population of the earth.

4 0

2 years ago

The density of o2 gas at 16 degrees Celsius and 1.27atm is?

velikii [3]

Answer:

The density of O₂ gas is 1.71 $\frac{g}{L}$

Explanation:

Density is a quantity that allows you to measure the amount of mass in a given volume of a substance. So density is defined as the quotient between the mass of a body and the volume it occupies:

$density=\frac{mass}{volume}$

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:

P * V = n * R * T

So, you can get:

$\frac{n}{V} =\frac{P}{R*T}$

The relationship between number of moles and mass is:

$n=\frac{mass}{molar mass}$

Replacing:

$\frac{\frac{mass}{molar mass} }{V} =\frac{P}{R*T}$

$\frac{mass}{V*Molar mass} =\frac{P}{R*T}$

So:

$\frac{mass}{V} =\frac{P*molar mass}{R*T}$

Knowing that 1 mol of O has 16 g, the molar mass of O₂ gas is 32 $\frac{g}{mol}$ .

Then:

$\frac{mass}{V} =\frac{P*molar mass of O_{2} }{R*T}$

In this case you know:

P=1.27 atm
molar mass of O₂= 32 $\frac{g}{mol}$ .

R= 0.0821 $\frac{atm*L}{mol*K}$

T= 16 °C= 289 °K (0°C= 273°K)

Replacing:

$density=\frac{mass}{V} =\frac{1.27atm*32\frac{g}{mol} }{0.0821\frac{atm*L}{mol*K} *289 K}$

Solving:

density= 1.71 $\frac{g}{L}$

The density of O₂ gas is 1.71 $\frac{g}{L}$

3 0

2 years ago

A 14.3-cm3 sample of tin has a mass of 0.104 kg.

VladimirAG [237]

This is a true statement if it is density you are looking for... Density problem.....

Density is the ratio of the mass of an object to its volume.
D = m / V
D = 104g / 14.3 cm³ = 7.27 g/cm³ .............. to three significant digits

The conventions for the units of density is that grams per cubic centimeter (g/cm³) are usually used for solids, but will work for anything. Grams per milliliter (g/mL) are usually used for liquids and grams per liter (g/L) are for gases. Therefore, by convention, the units for tin (a solid) should be in grams per cubic centimeter.

Since 1 mL is equivalent to 1 cm³, then the density could be expressed as 7.27 g/mL.

The accepted value for the density of tin is 7.31 g/cm³

7 0

2 years ago