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LUCKY_DIMON [66]
2 years ago
11

A survey of online students found that 52.6 percent believed they benefitted most from:_______a. Interacting with other students

on the discussion boards.b. Disagree with other students on the discussion boards.c. None of the above
Chemistry
1 answer:
kvv77 [185]2 years ago
5 0

Answer:

The answer is a): Interacting with other students on the discussion boards.

Explanation:

In a survey of online students who identified some tips that made them successful in online courses, and virtual university programs which targeted adults, 52.6 % of them believed that the greatest benefit they derived was due to their interaction with other students (especially classmates) on online discussion boards.

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Suppose you have exactly 1 cup (237 g) of hot (100.0 °C) brewed tea in an insulated mug and that you add to it 2.50 × 10² g of i
san4es73 [151]

Answer:

Final Temperature = 298.28 K (25.28°C)

Explanation:

First off, lets least out our parameters (What we were given).

Mass of Tea (Mt) = 237g

Initial temp. of tea (T1) = 100 °C + 273 = 373K (Converting  to Kelvin)

Mass of Ice (Mi) = 2.50 × 10² g = 250g

Initial temp. of ice (T1) = -18 °C + 273 = 255K (Converting  to Kelvin)

If all the ice melts

Amount of Heat required to melt the ice [H]  = Amount of heat required to raise its temperature to 0°C or 273K (Melting point) [H1] + Heat of Fusion [H2]

H1 = MiCΔT

ΔT = T2 - T1 = 255 - 273 = -18K

C = 2.09 J/gK (Specific Heat capacity of Ice)

H1 = 250 * 2.09 * (-18)

H1 = -9405 J

H2 = m·ΔHf

ΔHf = Heat of fusion of ice = 334 J/g

H2 = 250 * 334

H2 = 83500 J

Amount of Heat required to melt the ice [H] = H1 +  H2

H = -9405 + 83500 = 74095 J

This means the heat was able to supply 74095 J to the tea.

Final temperature is calculated from:

H = MtCΔT

ΔT = H/MtC

ΔT = 74095/(237 * 4.184)

ΔT = 74095 / 991.61

ΔT = 74.72 K

With a temperature difference of 74. 72 K

Final temperature  = Initial temperature - 74.72K

T2 = 373 - 74.74

T2 = 298.28 K (25.28°C)

6 0
2 years ago
Describe how to prepare the solution using a 250.0 mL volumetric flask by placing the steps in the correct order. Not all of the
padilas [110]

Answer:

The correct order will be

a. Transfer the measured amount of NaCl to the volumetric flask.

e. Dissolve the NaCl in less than 250 mL of water and mix well.

b. Dilute the solution with water to the 250.0 mL mark.

Explanation:

Preparation of NaCl solution in 250.0 ml volumetric flask:

Add the weighed NaCl directly to volumetric flask and add small amount of water to it and mix it will until all NaCl gets dissolved( if not add small water amount of water more)

After dissolving NaCl add the water upto the mark.

The correct order will be

a. Transfer the measured amount of NaCl to the volumetric flask.

e. Dissolve the NaCl in less than 250 mL of water and mix well.

b. Dilute the solution with water to the 250.0 mL mark.

6 0
2 years ago
What elements are in NaC2HO4 and how many atoms are in each element​
JulijaS [17]

Answer:

Each molecule contains one atom of A and one atom of B. The reaction does not use all of the atoms to form compounds.

                 A + B ⟶ Product

Particles: 6      8              6

If six A atoms form six product molecules, each molecule can contain only one A atom.

The formula of the product is ABₙ.

If n = 1, we need six atoms of B.

If n = 2, we need 12 atoms of B. However, we have only eight atoms of B, so the formula of the product must be AB.

Thus, 6A + 6B ⟶ 6AB, with two B atoms left over.

Explanation:

Credit goes to @znk

Hope it helps you :))

7 0
1 year ago
A chemical engineer must calculate the maximum safe operating temperature of a high-pressure gas reaction vessel. The vessel is
Inessa05 [86]

Answer:

T=2.78x10^3 \°C

Explanation:

Hello,

In this case, considering that the safe temperature may be computed via the ideal gas law as we now the pressure, mass and volume via the dimensions:

V=\pi r^2 h=\pi *(41.0cm)^2*49.2cm=2.60x10^5cm^3*\frac{1L}{1000cm^3} =260L

The pressure in atm is:

P=3.70MPa*\frac{1x10^6Pa}{1MPa} \frac{1atm}{101325Pa} =36.5atm

And the moles considering the mass and molar mass (66 g/mol) of dinitrogen difluoride (N₂F₂):

n_{N_2F_2}=2.50kg*\frac{1000g}{1kg}*\frac{1mol}{66g} =37.9mol

In sich a way, by applying the ideal gas equation, which is not the best assumption but could work as an approximation due to the high temperature, the temperature, with three significant figures, will be:

T=\frac{PV}{nR}=\frac{36.5Pa*260L}{37.9mol*0.082\frac{atm*L}{mol*K} }\\  \\T=3053.6K-273.15\\\\T=2.78x10^3 \°C

Best regards.

7 0
1 year ago
(1.) 163.26 g/mol, C11H17N
qwelly [4]

Answer:

75

Explanation:

4 0
1 year ago
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