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Vinvika [58]
2 years ago
15

Elements are abbreviated with blank , which consist of one or two blank

Chemistry
1 answer:
True [87]2 years ago
7 0
Chemical symbols are shorthand abbreviations<span> of the names of the 109 known </span>elements. Each element<span> ... Chemical symbols are </span>composed of one or two<span> letter</span>
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Select the NMR spectrum that corresponds best to p-bromoaniline. (see Hint for the structure.) The selected tab will be highligh
lana [24]

Answer:

The NMR spectrum that corresponds best to p-bromoaniline  is the one that is attached in the image below.

Explanation:

For the p-bromoaniline 3 types of hydrogen are observed. The first signal that appears at 3.7 ppm would be from the hydrogens of the NH2 group, the hydrogens in ortho position with respect to the NH2 group give a double at approximately 6.54 ppm, and finally the characteristic 7.21 ppm signal is observed for the hydrogens in meta position with with respect to the NH2 group.

7 0
2 years ago
An amount of solid barium chloride, 20.8 g, is dissolved in 100 g water in a coffee-cup calorimeter by the reaction: BaCl2 (s) 
mamaluj [8]

Answer : The enthalpy change during the reaction is -6.48 kJ/mole

Explanation :

First we have to calculate the heat gained by the reaction.

q=m\times c\times (T_{final}-T_{initial})

where,

q = heat gained = ?

m = mass of water = 100 g

c = specific heat = 4.04J/g^oC

T_{final} = final temperature = 26.6^oC

T_{initial} = initial temperature = 25.0^oC

Now put all the given values in the above formula, we get:

q=100g\times 4.04J/g^oC\times (26.6-25.0)^oC

q=646.4J

Now we have to calculate the enthalpy change during the reaction.

\Delta H=-\frac{q}{n}

where,

\Delta H = enthalpy change = ?

q = heat gained = 23.4 kJ

n = number of moles barium chloride = \frac{\text{Mass of barium chloride}}{\text{Molar mass of barium chloride}}=\frac{20.8g}{208.23g/mol}=0.0998mole

\Delta H=-\frac{646.4J}{0.0998mole}=-6476.95J/mole=-6.48kJ/mole

Therefore, the enthalpy change during the reaction is -6.48 kJ/mole

8 0
2 years ago
In a group assignment, students are required to fill 10 beakers with 0.720 M CaCl2. If the molar mass of CaCl2 is 110.98 g/mol a
8_murik_8 [283]
The answer is 200 g.

If the molar mass of CaCl2 is 110.98 g/mol, this means there are 110.98 g in 1 L of 1 M solution.
Let's find how many g of CaCl2 are present in 0.720 M.
110.98 g : 1 M = x : 0.720 M
x = 110.98 g * 0.720 M : 1 M 
x = 79.90 g

So there are 79.90 g in 0.720 M. In other words, in 1 L of 0.720 M solution there will be  79.90 g.

Now, we need to prepare ten beakers with 250 mL of solutions:
10 * 250 mL = 2500 mL = 2.5 L

79.90 g : 1 L = x : 2.5 L
x = 79.90 g * 2.5 L : 1 L
x = 199.75 g ≈ 200 g
8 0
2 years ago
Read 2 more answers
If the pressure P applied to a gas is increased while the gas is held at a constant temperature, then the volume V of the gas wi
yuradex [85]

Answer:

For these types of questions the equation that we must take into account is that:

T = PxV (where T is the temperature, P is the pressure and V is the volume) this equation is described as we consider that this is the value N and R is 1, therefore it is not necessary to explain them now.

Explanation:

The quoted equation refers to Boyle's Law, in this law we can explain that the volume increases if the pressure decreases and if the temperature also increases, if the pressure increases and the volume decreases this means that the gas is compressing assuming that the temperature is constant

8 0
2 years ago
Read 2 more answers
Synthesis of disubstituted benzenes involves two steps, each introducing one of the functional groups. For the synthesis of p-ch
Setler79 [48]

Answer:

The synthesis of p-chlorobenzenesulfonic acid with the reagents for each step and the structure of the monosubstituted intermediate compound is shown in the drawing below.

Explanation:

Benzenesulfonic acid is obtained from the sulfonation of benzene, using concentrated smoking sulfuric acid.

Chlorination of benzenesulfonic acid with chlorine without catalyst requires a polar solvent, such as acetic acid to obtain the selectivity in the position for and the ortho derivative in a low proportion.

7 0
2 years ago
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