Answer:
Each student will need;
1 red jelly bean, 1 white jelly bean, 1 black jelly bean and 3 red jelly beans.
Explanation:
Sodium bicarbonate molecule, NaHCO3, or baking soda is composed of the following:
1 atom of sodium, Na;
1 atom of hydrogen, H;
1 atom of carbon, C, and
3 atoms of oxygen.
For each of the models to be built by the two students, these atoms are to be represented accordingly.
Since Red jelly beans represent sodium atoms (Na), white jelly beans represent hydrogen atoms (H), black jelly beans represent carbon atoms (C), and blue jelly beans represent oxygen atoms (O), each student will need;
1 red jelly bean, 1 white jelly bean, 1 black jelly bean and 3 red jelly beans.
A sample model is found in the attachment below:
Answer:
Explanation:
<u>Calculation of the mass of chromium as:-
</u>
Moles = 1.002 moles
Molar mass of chromium = 51.9961 g/mol
The formula for the calculation of moles is shown below:
Thus,
<u>Calculation of the mass of neon as:-
</u>
Moles = 
moles
Molar mass of neon = 20.1797 g/mol
Thus,
it´s actually Lithium and fluorine / Magnesium and Chlorine / Beryllium and Nitrogen
An example.
water is H2O
2 hydrogen, 1 oxygen
so the number to the right means how much of what is on the left.
so it looks like 2, because C2, but look at the 3 at the beginning. that means
3 (c2h4)
so 6 carbons, 12 hydrogen
the ratio of c2 to h4 doesn't change it's always 1:2.
but the 3 at the front is a different number relating to how much you have
The Molecule of Sodium Formate along with Formal Charges (in blue) and lone pair electrons (in red) is attached below.
Sodium Formate is an ionic compound made up of a positive part (Sodium Ion) and a polyatomic anion (Formate).
Nomenclature:
In ionic compounds the positive part is named first. As sodium ion is the positive part hence, it is named first followed by the negative part i.e. formate.
Name of Formate:
Formate ion has been derived from formic acid ( the simplest carboxylic acid). When carboxylic acids looses the acidic proton of -COOH, they are converted into Carboxylate ions.
E.g.
HCOOH (formic acid) → HCOO⁻ (formate) + H⁺
H₃CCOOH (acetic acid) → H₃CCOO⁻ (acetate) + H⁺
Formal Charges:
Formal charges are calculated using following formula,
F.C = [# of Valence e⁻] - [e⁻ in lone pairs + 1/2 # of bonding electrons]
For Oxygen:
F.C = [6] - [6 + 2/2]
F.C = [6] - [6 + 1]
F.C = 6 - 7
F.C = -1
For Sodium:
F.C = [1] - [0 + 0/2]
F.C = [1] - [0]
F.C = 1 - 0
F.C = +1
