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Stella [2.4K]
2 years ago
8

Which of the following represents a pair of isotopes? Select one: a. 146C, 147N b. 11H, 21H c. 136C, 147N d. O2, O3 e. 3216S, 32

16S2- Check
Chemistry
1 answer:
skad [1K]2 years ago
3 0

Answer:

B

Explanation:

Isotopy is a phenomenon in which there exists two or more kind of atoms of the same element. These atoms have the same number of protons but different mass numbers. That is, they have the same atomic number but differ only by the number of neutrons in the nucleus of the atom. Now, let us apply this information to the options individually:

A. Is wrong, they are not the same element

B. Is correct. they both belong to the same element hydrogen. Infact, they are named protium and deuterium respectively

C is wrong they are not same element

D is wrong They are not elements at all

E. Is wrong, one is an element, the other is a molecule

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How many significant figures the measurement have 56.0g 0.0004m 1003ml 0.0350s
Setler [38]
In order to do this, we have to first know the significant figure rules.
<span>Rule #1: All non-zero digits are significant. (1234)
 Rule #2: Zeros in front of a number are not significant. (0.093)
 Rule #3: Zeros between non-zero digits are significant. (78309)
 Rule #4: Zeros at the end of a number are significant if there is a decimal point in the number. (0.05470)

So by going by the rules, 56.0g has three sig figs, because there is a decimal point.
0.0004m only has one sig fig, according to Rule #2.
1003ml has 4 sig figs, because the zeroes are wedged in the two sig fig numbers.
And lastly, 0.0350s has 3 sig figs because the number after a decimal point counts.

</span>
7 0
2 years ago
What is the percentage of water in the following compound? Answer using three significant figures. Sodium carbonate decahydrate,
Karo-lina-s [1.5K]
The trick for this problem is to understand atomic mass: the fact that different atoms have different masses. What we need to do is add up all the atomic masses of the compound and work out the ratio of mass of water to the mass of sodium carbonate. Atomic masses are often given for each atom in the periodic table, but you can look them up on google too.

You can do this by adding up individual atoms for each molecule, or you can shortcut and lookup the molar mass of the compound (i.e.the task already done for you). 

The molar mass of water is 18.01g/mole so for 10 moles of water we have a mass of 180.1g.


The molar mass of sodium carbonate is 106g/mole (google).

So the total mass of the sodium carbonate decahydrate compound is 180.1+106 = 286.1g, of which water would make up 180.1g, so the percentage of water is is 180.1/286.1 = 0.629, so we can round this to 63%

:)




3 0
2 years ago
Read 2 more answers
A 220.0 gram piece of copper is dropped into 500.0 grams of water 24.00 °C. If the final temperature of water is 42.00 °C, what
FrozenT [24]

Answer:

C. 481 °C.

Explanation:

  • At equilibrium:

The amount of heat absorbed by water = the amount of heat released by copper.

  • To find the amount of heat, we can use the relation:

<em>Q = m.c.ΔT,</em>

where, Q is the amount of energy.

m is the mass of substance.

c is the specific heat capacity.

ΔT is the difference between the initial and final temperature (ΔT = final T - initial T).

<em>∵ Q of copper = Q of water</em>

∴ - (m.c.ΔT) of copper = (m.c.ΔT) of water

m of copper = 220.0 g, c of copper = 0.39 J/g °C, ΔT of copper = final T - initial T = 42.00 °C - initial T.

m of water = 500.0 g, c of water = 4.18 J/g °C, ΔT of water = final T - initial T = 42.00 °C - 24.00 °C = 18.00 °C.

∴ - (220.0 g)( 0.39 J/g °C)(42.00 °C - Ti) = (500.0 g)(4.18 J/g °C)(18.00 °C)

∴ - (85.8)(42.00 °C - Ti) = 37620.

∴ (42.00 °C - Ti) = 37620/(- 85.8) = - 438.5.

∴ Ti = 42.00 °C + 438.5 = 480.5°C ≅ 481°C.

<em>So, the right choice is: C. 481 °C.</em>

4 0
2 years ago
A sample of the chiral molecule limonene is 79% enantiopure. what percentage of each enantiomer is present? what is the percent
Degger [83]

Answer :  The % of (+) limonene isomer = 79%


                The % of (-) limonene isomer = 0%


                The % of enantiomeric excess = 58%


Explanation :   Enantiomeric excess (ee) is the measurement of purity used for chiral substances.


Given,


% of pure limonene enantiomer = The % of (+) limonene isomer = 79%


Therefore, The % of (-) limonene isomer = 0%


Formula used :  

\%(+)\text{ isomer}=\frac{ee}{2}+50\%


Where,         ee → enantiomeric excess


Now, put all the values in above formula, we get the value of enantiomeric excess (ee).


     {ee}=\frac{\%(+)-50\%}{2}


            =\frac{79\%-50\%}{2}


              = 58%



7 0
2 years ago
Read 2 more answers
Draw a second resonance structure for the following ion (be sure to include the charges and all lone pairs)... + ..N=N=N &lt;---
joja [24]

Answer:

Explanation:

Resonance structure occurs in an organic compound that undergoes resonance effects. This resonance effect is sometimes called the mesomeric effect helps to increases the stability of organic compounds that have alternating single bonds and double bonds.

The second resonance structure diagram for the ion given in the question can be found in the attached diagram below.

8 0
2 years ago
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