If 1 kg of mass disappeared, this only means that all of
those mass was converted to energy. We can actually compute for the energy using
the formula:
E = m c^2
where m is mass and c is speed of light:
E = 1 kg * (3 x 10^8 m/s^2)2
E = 9 x 10^16 J
Answer: the original volume was 0.98L
Explanation:
V1 =?
T1 = 22k
V2 = 3.8L
T2 = 85k
V1 /T1 = V2 /T2
VI/22 = 3.8/85
V1 = 22 x (3.8/85)
V1 = 0.98L
<u>Answer:</u> The volume of carbon dioxide gas at STP for given amount is 106.624 L
<u>Explanation:</u>
We are given:
Moles of carbon dioxide = 4.76 moles
<u>At STP:</u>
1 mole of a gas occupies a volume of 22.4 Liters
So, for 4.76 moles of carbon dioxide gas will occupy a volume of = 
Hence, the volume of carbon dioxide gas at STP for given amount is 106.624 L
Answer: In the given reaction increasing the amount of solution is likely to increase the rate of the reaction.
Explanation:
It is known that more is the number of reactant molecules taking part in a chemical reaction more will be the number of collisions occur. As a result, more will be the rate of chemical reaction.
For example, When hydrogen peroxide dissociates into water and oxygen on addition of manganese oxide then increasing the number of reactants (hydrogen peroxide and manganese oxide) will also lead in the increase in rate of reaction.
Thus, we can conclude that in the given reaction increasing the amount of solution is likely to increase the rate of the reaction.
The trick for this problem is to understand atomic mass: the fact that different atoms have different masses. What we need to do is add up all the atomic masses of the compound and work out the ratio of mass of water to the mass of sodium carbonate. Atomic masses are often given for each atom in the periodic table, but you can look them up on google too.
You can do this by adding up individual atoms for each molecule, or you can shortcut and lookup the molar mass of the compound (i.e.the task already done for you).
The molar mass of water is 18.01g/mole so for 10 moles of water we have a mass of 180.1g.
The molar mass of sodium carbonate is 106g/mole (google).
So the total mass of the sodium carbonate decahydrate compound is 180.1+106 = 286.1g, of which water would make up 180.1g, so the percentage of water is is 180.1/286.1 = 0.629, so we can round this to 63%
:)
