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11111nata11111 [884]
2 years ago
11

Complete the reaction, which is part of the electron transport chain. The abbreviation FMN represents flavin mononucleotide. Use

the appropriate abbreviation for the product. NADH + H + + FMN ⟶ NAD +FMNH_{2} NAD + FMNH 2 The reactant that is reduced is FMN . In complex III, electrons are transferred from coenzyme Q to cytochrome c, which contains iron. QH 2 + 2 cyt c ( Fe 3 + ) ⟶ Q + 2 cyt c ( Fe x ) + 2 H + Determine the oxidation number for iron on the right side of the reaction arrow.
Chemistry
1 answer:
erik [133]2 years ago
4 0

Answer:

Oxidation number of Fe(iron) on right side of reaction arrow = (+2)

Explanation:

NADH+H+ + FMN   FMNH2 + NAD+

FMNH2 - Reduced FMN (1,5-Dihydroriboflavin 5'-(dihydrogen phosphate)

The reactant that is reduced is Flavin mononucleotide(FMN)

QH2 + 2cyt c(fe³+)  ----------------------->  Q + 2Cytc ( fe²+) + 2H+

Oxidation number of Fe(iron) on right side of reaction arrow = (+2)

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Trial 2, because the amount of product formed per unit time is higher.

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A 0.20 mol sample of MgCl2(s) and a 0.10 mol sample of KCl(s) are dissolved in water and diluted to 500 mL. What is the concentr
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Answer:

1 M

Explanation:

Magnesium chloride will furnish chloride ions as:

MgCl_2\rightarrow Mg^{2+}+2Cl^-

Given :

Moles of magnesium chloride = 0.20 mol

Thus, moles of chlorine furnished by magnesium chloride is twice the moles of magnesium chloride as shown below:

Moles =2\times 0.20\ moles

Moles of chloride ions by magnesium chloride = 0.40 moles

Potassium chloride will furnish chloride ions as:

KCl\rightarrow K^{+}+Cl^-

Given :

Moles of potassium chloride = 0.10 moles

Thus, moles of chlorine furnished by potassium chloride is same as the moles of potassium chloride as shown below:

Moles of chloride ions by potassium chloride = 0.10 moles

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Given, Volume = 500 mL = 0.5 L (1 mL = 10⁻³ L)

Concentration of chloride ions is:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

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A compound that is composed of carbon, hydrogen, and oxygen contains 70.6% C, 5.9% H, and 23.5% O by mass. The molecular weight
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Answer: The molecular formula will be C_8H_8O_2

Explanation:

If percentage are given then we are taking total mass is 100 grams.

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Step 1 : convert given masses into moles.

Moles of C =\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{70.6g}{12g/mole}=5.9moles

Moles of H =\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{5.9g}{1g/mole}=5.9moles

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Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = \frac{5.9}{1.5}=4

For H = \frac{5.9}{1.5}=4

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n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{136}{68}=2

The molecular formula will be=2\times C_4H_4O=C_8H_8O_2

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