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Salsk061 [2.6K]
1 year ago
6

A liquid's freezing point is -38°C and it's boiling point is 357°C. What is the number of Kelvin between the boiling point and t

he freezing point of the liquid?
Chemistry
1 answer:
laiz [17]1 year ago
7 0
The Kelvin temperature K =℃ + 273.15. ℃ means centigrade temperature. So the centigrade temperature number between freezing point and boiling point is equal to the number of Kelvin. So the answer is 357-(-38)=395.
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How many moles of gas Does it take to occupy 520 mL at a pressure of 400 torr and a temperature of 340 k
Ann [662]
Answer would be B. I provided work on an image attached. Message me if u have any other questions on how to do it

6 0
1 year ago
A solution of HCl has StartBracket upper H superscript plus EndBracket. = 0.01 M. What is the pH of this solution?
hoa [83]

Answer:

2

Explanation:

Data:

[H⁺] = 0.01 mol·L⁻¹

Calculation:

pH = -log[H₃O⁺] = -log(0.01) = -log(1) - log(10⁻²) = -0 - (-2) = 0 + 2 = 2

7 0
1 year ago
Click the "draw structure" button to launch the drawing utility. Propane (CH3CH2CH3) has both 1° and 2° hydrogens. Draw the carb
OlgaM077 [116]

Answer:

a) find attached image 1

b) find attached image 2

Explanation :

The more stable radical is formed by a reaction with smaller bond dissociation energy.

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6 0
2 years ago
6.74 g of the monoprotic acid KHP (MW = 204.2 g/mol) is dissolved into water. The sample is titrated with a 0.703 M solution of
Dennis_Churaev [7]

Answer:

Volume of the calcium hydroxide solution used is 0.0235 mL.

Explanation:

2KHP+Ca(OH)_2\rightarrow 2H_2O+Ca(KP)_2

Moles of KHP = \frac{6.74 g}{204.2 g/mol}=0.0330 mol

According to reaction, 2 moles of KHP  with 1 mole of calcium hydroxide , then 0.0330 moles of KHP will recat with ;

\frac{1}{2}\times 0.0330 mol=0.01650 mol of calcium hydroxide

Molarity of the calcium hydroxide solution = 0.703 M

Volume of calcium hydroxide solution = V

Molarity=\frac{Moles}{Volume(L)}

0.703 M=\frac{0.01650 M}{V}

V=\frac{0.01650 M}{0.703 M}=0.0235 mL

Volume of the calcium hydroxide solution used is 0.0235 mL.

4 0
2 years ago
a student adds 3.5 moles of solute to enough water to make a 1500mL solution. what is the concentration?
aksik [14]
<h2>Hello!</h2>

The answer is:

MolarConcentration=\frac{3.5moles}{volume(1.5L)}=2.33molar

<h2>Why?</h2>

Since there is not information about the solute but only its mass, we need to assume that we are calculating the molar concentration of a solution or molarity. So, need to use the following formula:

MolarConcentration=\frac{mass(solute)}{volume(solution)}

Now, we know that the mass of the solute is equal  3.5 moles and the volume is equal to 1500 mL or 1.5L

Then, substituting into the equation, we have:

MolarConcentration=\frac{3.5moles}{1.5L}=2.33molar

Have a nice day!

7 0
1 year ago
Read 2 more answers
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