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elixir [45]
1 year ago
5

The percentage of silver in a solid sample is determined gravimetrically by converting the silver to Ag+ (aq) and precipitating

it as silver chloride. Failure to do which of the following could cause errors in the analysis?I Account for the mass of the weighing paper when determining the mass of the sampleII Measure the temperature during the precipitation reactionIII Wash the precipitateIV Heat the AgCl precipitate to constant mass(A) I & II
(B) I & IV
(C) II & III
(D) I, III, & IV
Chemistry
2 answers:
Wittaler [7]1 year ago
8 0

Answer:

D

Explanation:

I - You should account the mass of the weighing paper to reduce it from the total mass at the end of the process, having only the mass of the Silver Chloride.

II - The precipitation of the silve chloride will occur independently of the temperature, because the Kps of this salt is very low (Ksp = [Ag+] .[Cl-]).

III - Washing the precipitate will secure the purity of the final product, it won't allow any other contaminant to be in your precipitante which could change your final mass.

IV - You should heat you AgCl precipitate so it will be dry, because of that the mass you will obtain is only the mass of the weighing paper and the silver chloride and nothing else.

nika2105 [10]1 year ago
5 0

Answer:(D) I, III, & IV

Explanation:

Firstly, the precipitate needs to be washed to remove water soluble impurities adsorbed on the surface of the precipitate which could affect its mass. Secondly, the precipitate must be heated to constant mass to drive off solvent molecules that adhered to the solid and could inflate the mass of the precipitate thereby introducing error to the analysis. The mass of the weighing paper must be accounted for because the mass read from the balance is the mass of the sample+ weighing paper.

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Using only the following elements P, Br, and Mg, give the formulas for:A. an ionic compound. B. a molecular compound with polar
Talja [164]

Answer:

<h2>1. Ionic compound- MgBr_2</h2><h2>2. Polar molecular compound- PBr_3</h2>

Explanation:

Mg is a metal that has 12 atomic numbers and thus its electronic configuration is 1s^22s^22p^63s^2. The outer most shell of this element has 2 electrons so it loses 2 electrons and thus form Mg^2^+ ions. Br is a nonmetal and has 35 atomic number so its electronic configuration is 1s^22s^22p^63s^23p^64s^23d^1^04p^5. Since its outermost shell has 7 electrons so it can accept one electron and thus forms Br^-. So magnesium ion and bromide ion combine and forms an ionic compound MgBr_2.

P is also a nonmetal and combine with Br with covalent bond and due to electronegativity differences form polar covalent compound such as PBr_3.

8 0
1 year ago
A kettle of water is at 14.5°C. Its temperature is then raised to 50.0°C by supplying it with 5,680 joules of heat. The specific
Tamiku [17]

Answer:- 38.2 g.

Solution:- The equation used for solving this type of calorimetry problems is:

q=mc\Delta T

where, q is the heat energy, m is mass, c is specific heat and delta T is the change in temperature.

Water temperature is increasing from 14.5 degree C to 50.0 degree C.

\Delta T=50.0-14.5  = 35.5 degree C

q is given as 5680 J and specific heat value is 4.186\frac{J}{g.^0C} .

The equation could be rearranged for m as:

m=\frac{q}{c*\Delta T}

Let's plug in the values in it:

m=\frac{5680}{4.186*35.5}

m = 38.2 g

So, the mass of water in the kettle is 38.2 g.


4 0
2 years ago
Read 2 more answers
A higher temperature of fresh concrete results in a __________ hydration of cement.
Readme [11.4K]

Answer:

more rapid

Explanation:

A higher temperature of fresh concrete results in a more rapid hydration of cement. This causes reduction in the setting time of the cement, also known as accelerated setting of the cement.

It also reduces the workability of the concrete; as it makes the movement of aggregates harder by reducing the lubricating effect of the cement.

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2 years ago
Perform the following
Ghella [55]

Answer:

1.85 × 10⁻⁶

Explanation:

0.0003 ÷ 162 = 1.851851852 × 10⁻⁶ ⇒ 1.85 × 10⁻⁶

Hope that helps.

4 0
1 year ago
In Part A, you found the amount of product (1.80 mol P2O5 ) formed from the given amount of phosphorus and excess oxygen. In Par
Finger [1]

First step is to balance the reaction equation. Hence we get P4 + 5 O2 => 2 P2O5

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2.5 mol of O2 will react with 0.7 mol of P2O5 to produce 1.4 mol of P2O5.

This is 1.4 * (31*2 + 16*5) = 198.8 g

3 0
2 years ago
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