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2 years ago

Why does iron not fit the pattern in column 7

1 answer:

3 0

Iron doesn't fit because it doesn't have enough atoms or protons in its nucleus so there for it belongs in column 2.

You might be interested in

What is the empirical formula of a substance that contains 0.117 mol of carbon, 0.233 mol of hydrogen, and 0.117 mol of oxygen?

Rzqust [24]

Empirical formula of a compound gives the proportions of the elements in that compound but it does not define the actual arrangement and number of atoms.

Let the empirical formula of compound be $C_{x}H_{y}O_{z}$ .

The ratio of number of moles of C, H and O can be calculated as follows:

$C:H:O=0.117:0.233:0.117$

Simplifying the ratio,

$C:H:O=\frac{0.117}{0.117}:\frac{0.233}{0.117}:\frac{0.117}{0.117}=1:1.99:1=1:2:1$

Thus, the value of x, y and z will be 1, 2 and 1 respectively.

Therefore, the empirical formula will be $CH_{2}O$ .

6 0

1 year ago

A metallic object holds a charge of −4.8 × 10−6 C. What total number of electrons does this represent? (e = 1.6 × 10−19 C is the

vagabundo [1.1K]

Answer:

$n=3.0\times 10^{13}$

Explanation:

Charge on 1 electron = $-1.6\times 10^{-19}\ C$

The expression for charge is:-

$Charge=n\times q_e$

Given that:- Charge = $-4.8\times 10^{-6}\ C$

$-4.8\times 10^{-6}=n\times (-1.6\times 10^{-19})$

$n=\frac{4.8\times 10^{-6}}{1.6\times 10^{-19}}=3.0\times 10^{13}$

Total number of electrons, n = $3.0\times 10^{13}$

5 0

1 year ago

In E. coli, the enzyme hexokinase catalyzes the reaction: Glucose + ATP → glucose 6-phosphate + ADP The equilibrium constant, Ke

kondor19780726 [428]

Answer:

Explanation:

Glucose + ATP → glucose 6-phosphate + ADP The equilibrium constant, Keq, is 7.8 x 102.

In the living E. coli cells,

[ATP] = 7.9 mM;

[ADP] = 1.04 mM,

[glucose] = 2 mM,

[glucose 6-phosphate] = 1 mM.

Determine if the reaction is at equilibrium. If the reaction is not at equilibrium, determine which side the reaction favors in living E. coli cells.

The reaction is given as

Glucose + ATP → glucose 6-phosphate + ADP

Now reaction quotient for given equation above is

$q=\frac{[\text {glucose 6-phosphate}][ADP]}{[Glucose][ATP]}$

$q=\frac{(1mm)\times (1.04 mm)}{(7.9mm)\times (2mm)} \\\\=6.582\times 10^{-2}$

so,

$q$ ⇒ following this criteria the reaction will go towards the right direction ( that is forward reaction is favorable until q = Keq

4 0

1 year ago

the image above shows a chamber with a fixed volume filled with gas at a pressure of 1560 mmHg and a temperature of 445.0 K. If

Sedaia [141]

Answer:

The new pressure of the gas in the chamber is 1,093.75 mmHg

Explanation:

The Gay-Lussac Law is a gas law that relates pressure and temperature to constant volume. This law says that the pressure of the gas is directly proportional to its temperature.

That is, if the temperature increases, the pressure increases, while if the temperature decreases, the pressure decreases. So the Gay-Lussac law can be expressed mathematically as follows:

$\frac{P}{T} =k$

Having an initial and an end state of a gas, the following expression can be used:

$\frac{P1}{T1} =\frac{P2}{T2}$

In this case:

P1= 1560 mmHg
T1= 445 K
P2=?
T2= 312 K

Replacing:

$\frac{1560 mmHg}{445 K} =\frac{P2}{312 K}$

Solving:

$P2=\frac{1560 mmHg}{445 K} *312K$

P2=1,093.75 mmHg

The new pressure of the gas in the chamber is 1,093.75 mmHg

7 0

1 year ago

How many moles of O2 are produced when 0.500mol of KO2 reacts in this fashion?

Shtirlitz [24]

I think you means the KO2 reacts with H2O. The equation of this reaction is 4KO2+2H2O->4KOH +3O2. The ratio of mole number of O2 and KO2 is 3:4. So the mole number of O2 produced is 0.500/4*3=0.375 mol.

6 0

1 year ago