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nadya68 [22]
2 years ago
7

Certain glass objects are not meant to be heated and could shatter if exposed to a heat source. What two examples of heat-sensit

ive glassware are given in the video?
Chemistry
1 answer:
Stels [109]2 years ago
8 0

Answer: the heat-sensitive glassware that were given are : Volumetric and Graduated cylinder.

Explanation:glass material that reacts to ambient temperatures radiated off of other surfaces like hands or water is known as heat sensitive glassware. They are not meant to be heated and could shatter if exposed to a heat source. Examples from the video includes Volumetric and Graduated cylinder. Hope this helps. Thanks.

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A sample of fluorine gas is confined in a 5.0-L container at 0.432 atm and 37 °C. How many moles of gas are in this sample?
Ahat [919]

Answer:

About 0.08486 moles

Explanation:

PV=nRT, when P is the pressure in atmospheres, V is the volume in liters, n is the number of moles, R is the universal gas constant, and T is the temperature in Kelvin.

0.432 \cdot 5= n \cdot 0.0821 \cdot 310

n\approx 0.08486 moles

Hope this helps!

7 0
2 years ago
Mori walks into a restaurant. Upon smelling the food cooking, her mouth starts to water. Which system in the body detected the i
VLD [36.1K]

Answer:

Digestive system

6 0
2 years ago
Read 2 more answers
in sample of elemental bromine, 55% or the atoms are Br-79, and the remainder are Br-81. if this sample is typical of naturally
Gwar [14]

Answer:

The average atomic mass of bromine is 79.9 amu.

Explanation:

Given data:

Percentage of Br⁷⁹ = 55%

Percentage of Br⁸¹ = 45%

Average atomic mass of bromine = ?

Formula:

Average atomic mass = [mass of isotope× its abundance] + [mass of isotope× its abundance] +...[ ] / 100

Now we will put the values in formula.

Average atomic mass = [55 × 79] + [81 ×45] / 100

Average atomic mass = 4345 + 3645 / 100

Average atomic mass = 7990 / 100

Average atomic mass = 79.9 amu

The average atomic mass of bromine is 79.9 amu.

3 0
2 years ago
Calculate the number of grams of solute in 500.0 mL of 0.189 M KOH.
KIM [24]

Answer : The number of grams of solute in 500.0 mL of 0.189 M KOH is, 5.292 grams

Solution : Given,

Volume of solution = 500 ml

Molarity of KOH solution = 0.189 M

Molar mass of KOH = 56 g/mole

Formula used :

Molarity=\frac{\text{Mass of KOH}\times 1000}{\text{Molar mass of KOH}\times \text{Volume of solution in ml}}

Now put all the given values in this formula, we get the mass of solute KOH.

0.189M=\frac{\text{Mass of KOH}\times 1000}{(56g/mole)\times (500ml)}

\text{Mass of KOH}=5.292g

Therefore, the number of grams of solute in 500.0 mL of 0.189 M KOH is, 5.292 grams

7 0
2 years ago
Read 2 more answers
A small hole in the wing of a space shuttle requires a 20.7-cm2 patch, (a) What is the patch's area in square kilometers (km2)?
bixtya [17]

Answer:

(a) The area of space shuttle is 2.07\times 10^{-9} km^2.

(b) $10.427 is the cost of the patch.

Explanation:

Area of the patch of the space shuttle = 20.7 cm^2

a) 1 cm = 0.00001 km

1 cm^2= (0.00001 km)^2=10^{-10}km^2

20.7 cm^2=20.7\times 10^{-10}km^2=2.07\times 10^{-9} km^2

b) 1 cm = 0.393701 inch

1 cm ^2=0.1550 inch^2

20.7 cm^2=20.7\times 0.1550 inch^2=3.2085 inch^2

Cost of patching area = \$3.25/inch^2

Cost of patching 3.2085 inch^2 are:

\$3.25/inch^2\times 3.2085 inch^2=\$10.427

8 0
2 years ago
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