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2 years ago

What is the name of a compound with the structure: ch3ch2ch2ch2ch2co2ch2ch2ch3?

1 answer:

5 0

4-nonanone
Explanation: there is a functional group in the compound CH3CH2CH2CH2CH2COCH2CH2CH3 which is a ketone; So for naming a ketone we must first mention the name of the prefix that is correspond then add the suffix ''one''. And why I putted a ''4'' before the name is because we must indicate where this functional group is located, for doing that we have to start counting where the functional group is the closet to the end of the compound so when looking we should start to count on the right side. this is how I get 4-nonanone

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The solubility of N2 in blood can be a serious problem (the "bends") for divers breathing compressed air (78% N2 by volume) at d

OLga [1]

Answer:

The volume is 19.7 mL

Explanation:

<u>Step 1</u>: Given data

Pressure at sea level = 1.00 atm

Pressure at 50 ft = 2.47535 atm

kH for N2 in water at 25°C is 7.0 × 10−4 mol/L·atm

Molarity (M) = kH x P

<u>Step 2</u>: Calculate molarity

M at sea level:

M = 7.0*10^-4 * (1.00atm * 0.78) = 5.46*10^-4 mol/L

M at 50ft:

M = 7.0*10^-4 * (2.47535atm * 0.78) = 13.5*10^-4 mol/L

We should find the volume of N2. To find the volume whe have to find the number of moles first. This we calculate by calculating the difference between M at 50 ft and M at sea level.

13.5*10^-4 mol/L - 5.46*10^-4 mol/L = 8.04*10^-4 mol/L

Step 3: Calculate volume

P*V=nRT

with P = 1.00 atm

with V = TO BE DETERMINED

with n = 8.04*10^-4 mol/L *1L = 8.04*10^-4

with R= 0.0821 atm * L/ mol *K

with T = 25 °C = 273+25 = 298 Kelvin

To find the volume, we re-organize the formula to: V=nRT/P

V= (8.04*10^-4 mol * 0.0821 (atm*L)/(mol*K)* 298K ) / 1.00atm = 0.0197L = 19.7ml

The volume is 19.7 mL

5 0

2 years ago

Given the statements:

olga nikolaevna [1]

C. The salt bridge maintains the flows of ions and allows electrons to move from the anode to the cathode.

3 0

2 years ago

Read 2 more answers

After recrystallization, the final weight of biphenyl is found to be 0.02 g. Assume that all steps were carried out correctly, n

Lubov Fominskaja [6]

Explanation:

From the source, The student recrystallized biphenyl by using benzene. Biphenyl is non polar and so is benzene. Biphenyl is very soluble in benzene at low as well as high temperature. Thus, it do not recrystallize as like dissolves like and gives a very poor yield.

The good recovery of the product is dependent on compound having high solubility at the high temperatures and having low solubility at the low temperatures.

6 0

2 years ago

What is the yield of uranium from 2.50 kg U3O8?

mr_godi [17]

Answer: Thus the yield of uranium from 2.50 kg $U_3O_8$ is 2.12 kg

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to molecular mass and contains avogadro's number $(6.023\times 10^{23})$ of particles.

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{molar mass}}$

moles of $U_3O_8=\frac{2.50\times 1000g}{842g/mol}=2.97mol$ (1kg=1000g)

As 1 mole of $U_3O_8$ contains = 3 moles of U

2.97 mole of $U_3O_8$ contains = $\frac{3}{1}\times 2.97=8.91moles$ moles of U

Mass of Uranium= $moles\times {\text {Molar mass}}=8.91mol\times 238g/mol=2120g=2.12kg$

( 1kg=1000g)

Thus the yield of uranium from 2.50 kg $U_3O_8$ is 2.12 kg

8 0

2 years ago

What is the molarity of a solution that contains 122g of MgSO4 n 3.5L of solution?

tatiyna

Answer:

0.29mol/L or 0.29moldm⁻³

Explanation:

Given parameters:

Mass of MgSO₄ = 122g

Volume of solution = 3.5L

Molarity is simply the concentration of substances in a solution.

Molarity = number of moles/ Volume

>>>>To calculate the Molarity of MgSO₄ we find the number of moles using the mass of MgSO₄ given.

Number of moles = mass/ molar mass

Molar mass of MgSO₄:

Atomic masses: Mg = 24g

S = 32g

O = 16g

Molar mass of MgSO₄ = [24 + 32 + (16x4)]g/mol

= (24 + 32 + 64)g/mol

= 120g/mol

Number of moles = 122/120 = 1.02mol

>>>> From the given number of moles we can evaluate the Molarity using this equation:

Molarity = number of moles/ Volume

Molarity of MgSO₄ = 1.02mol/3.5L

= 0.29mol/L

IL = 1dm³

The Molarity of MgSO₄ = 0.29moldm⁻³

6 0

2 years ago