Answer:
The mass of object is 0.5 Kg.
Explanation:
Given data:
Acceleration of object = 12.0 m/s²
Force on object = 6.0 N
Mass of object = ?
Solution:
Formula:
F = m×a
F = force
m = mass
a = acceleration
Now we will put the values in formula.
6.0 N = m × 12.0 m/s²
m = 6.0 N / 12.0 m/s²
( N = kg.m/s²)
m = 0.5 kg
The mass of object is 0.5 Kg.
Answer:
<em>The pKa is 13.0.</em>
Explanation:
pKa + pKb = 14
Given, Kb of trimethylamine = 6.3 × 
pKb = - log (6.3 × )
= 1.0
⇒ pKa = 14 - pKb = 14 - 1.0
<u>pKa = 13.0</u>
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<em>Check: For most weak acids, pKa ranges from 2 to 13.</em>
Answer:
1) 0.009 61 g C; 2) 0.008 00 mol C
Step-by-step explanation:
You know that you will need a balanced equation with masses, moles, and molar masses, so gather all the information in one place.
M_r: 12.01 44.01
C + ½O₂ ⟶ CO₂
m/g: 0.352
1) <em>Mass of C
</em>
Convert grams of CO₂ to grams of C
44.01 g CO₂ = 12.01 g C
Mass of C = 0.352 g CO₂ × 12.01 g C/44.01 g CO₂
Mass of C = 0.009 61 g C
2) <em>Moles of C
</em>
Convert mass of C to moles of C.
1 mol C = 12.01 g C
Moles of C = 0.00961 g C × (1 mol C/12.01 g C)
Moles of C = 0.008 00 mol C
All the carbon comes from Compound A, so there are 0.008 00 mol C in Compound A.
When solving for the mass of a compound when you’re given the number of moles present, you need to know the molar mass (how many grams there are in a mole of that compound).
In this case, we can make the following equation:
3.00(14.01 + 2(16.00))
In Nitrogen, the molar mass is 14.01 grams per mole, and Oxygen is 16.01 grams per mole.
However, because there are 2 oxygen atoms present per molecule, you must multiply it by two in order to solve for the molar mass.
Anyway:
3.00(14.01 + 2(16.00))
Simplify:
3.00(14.01 + 32.00)
3.00(46.01)
Multiply:
3.00(46.01) = 138.03
3.00 moles of NO2 has a mass of 138.03 grams.
-T.B.
