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dsp73
1 year ago
11

A water treatment tablet contains 20.0 mg of tetraglycine hydroperiodide, 40.0% of which is available as soluble iodine. If two

tablets are used to treat 1.00 liter of drinking water, what is the concentration in ppm of iodine in the treated water
Chemistry
1 answer:
Galina-37 [17]1 year ago
8 0

Answer:

16\ \text{ppm}

Explanation:

Mass of one tablet = 20 mg

Mass of two tablets = 2\times 20=40\ \text{mg}

Percent that is soluble in water = 40%

Mass of tablet that is soluble in water = 0.4\times 40=16\ \text{mg}

So, mass of solute is 16\ \text{mg}

Density of water = 1 kg/L

Volume of water = 1 L

So, mass of 1 L of water is 1\times 1=1\ \text{kg}=1000\ \text{g}

PPM is given by

\dfrac{\text{Mass of solute}}{\text{Mass of solvent}}\times 10^6=\dfrac{16\times 10^{-3}}{1000}\times 10^6\\ =16\ \text{ppm}

Hence, the concentration of iodine in the treated water 16\ \text{ppm}.

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A given sample of caffeine, C8H10N4O2, has 6.47 x 1022
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Answer:

<u>8.08 × </u>10^{22}<u> atoms of hydrogen</u>

Explanation:

From the given data, we have two categories of variables (unknowns):

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The longer route would be to solve for these variables first, by determining the number of moles of the Caffeine sample (0.134 moles of C8H10N4O2) from the mass of carbon (12.89 g = 1.07 moles in 6.47 10^{22} atoms) provided. And then solve for the number of atoms of H. <u><em>[N.B: 1 mole of ANY substance = 6.022 × </em></u>10^{22}<u><em> atoms ]</em></u>

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8 : 10 ≡ 4 : 5

If   4 moles -- 6.47 10^{22} atoms

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2 years ago
The flame produced by the burner of a gas (propane) grill is a pale blue color when enough air mixes with the propane (C3H8) to
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At the burner temp. and pressure, 18.85 litres of air is needed to completely combust each gram of propane

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R = 8.314

and we calculated n = number of moles air = 0.54 mol

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